Indentation of `then` in algorithms?

Question

I've already benefited from parbox command to apply some indentation to some lines of my algorithm.

Now, I need to apply indentation to then keyword. As then is automatically generated by \If or ElsIf, I can not use the typical trick of parbox for that.

What I need is depicted in following figure: each then keyword must be aligned w.r.t. its corresponding else if:

My MWE:

\documentclass[letterpaper, 10pt, conference]{IEEEconf}

\let\proof\relax
\let\endproof\relax

\usepackage{amsmath}
\usepackage{amssymb}
\usepackage{mathrsfs}
\usepackage{algorithm}
\usepackage{algorithmicx,algpseudocode}

\newcommand\Sth[1]{S^{#1}\mkern-3mu(\mkern-2.5mu\theta^{\mkern-1mu#1}\mkern-2mu)}

\title{My Title*}

\author{Guy$^{1}$
    \thanks{*This work was not supported by any organization}
    \thanks{$^{1}$Guy is with Hell, {\tt\small guy@hell.edu}}
}

\algnewcommand\algorithmicforeach{\textbf{for each}}
\algdef{S}[FOR]{ForEach}[1]{\algorithmicforeach\ #1\ \algorithmicdo}

\let\oldReturn\Return
\renewcommand{\Return}{\State\oldReturn}

\begin{document}

    \maketitle
    \thispagestyle{empty}
    \pagestyle{empty}

    \begin{abstract}

        ABSTRACT

    \end{abstract}

    \section{INTRODUCTION}

    \begin{algorithm}
        \renewcommand{\thealgorithm}{}
        \caption{algorithm}
        \label{euclid}
        \begin{algorithmic}[1] 
            \While{true}
            \ForEach{xxx}
            \State do $A$
            \If{nothing happened}
            \State \parbox[t]{\dimexpr\linewidth-\algorithmicindent}{$\text{updated var} \gets \varnothing$\strut}
            \ElsIf{objects lie inside the same operating space}
            \ForEach{object with sweeping function $S$}
            \State \parbox[t]{\dimexpr\linewidth-\algorithmicindent}{$\text{updated var} \gets S$\strut}  
            \EndFor
            \ElsIf{objects lie inside different operating space} 
            \ForAll{functions $B$}
            \ForAll{functions $C$}
            \State \parbox[t]{\dimexpr\linewidth-\algorithmicindent}{$\text{updated adjacency} \gets S$\strut}
            \EndFor
            \EndFor
            \EndIf
            \Return updated var
            \EndFor  
            \EndWhile\label{euclidendwhile}
        \end{algorithmic}
    \end{algorithm}
\end{document}

score 2 · Answer 1 · edited Apr 13 '17 at 12:36

2

There are no line numbers where then is - this is an indicator that this is not an own logical line.
It's just a line break because the text is too long in order to fit in one line.
I used a very small font size to show you where the logical line breaks occur.
You use a documentclass with two columns -- therefore the text width is pretty small.

(I used Show frame/margin in two column layout to show the borders.)

Indentation of `then` in algorithms?

1 Answers1

Related Links Regarding the Width of the `algorithm` Environment

Indentation of `then` in algorithms?

1 Answers1

Related Links Regarding the Width of the algorithm Environment

Related Links Regarding the Width of the `algorithm` Environment