This question is the following of this one. The solution worked very well (Thanks so much JPI !) but it remains another request : with the previous code (without the 1st solution by JPI) I could use polynomial command with \dfrac{2}{3} as one of the arguments. And it worked ! Now (with the JPI's solution) it doesn't. Question : is there a solution to both requirements ?
The following (without JPI's code) is the code leading to the following result :
\FPeval\VRcoeffa{(0-1)} \FPclip\VRcoeffa{\VRcoeffa}
\FPeval\VRcoeffb{(8/3)} \FPclip\VRcoeffb{\VRcoeffb}
\FPeval\VRcoeffc{(0)} \FPclip\VRcoeffc{\VRcoeffc}
\FPeval\VRcoeffd{(0-12)} \FPclip\VRcoeffd{\VRcoeffd}
\FPeval\VRcoeffe{(1)} \FPclip\VRcoeffe{\VRcoeffe}
\FPeval\VRcoefff{(0-1)} \FPclip\VRcoefff{\VRcoefff}
\FPset\toto{\dfrac{2}{3}}
$f(x)=\polynomial[reciprocal]{%
\VRcoeffa,%
\dfrac{2}{3},%
\VRcoeffc,%
\VRcoeffd,%
\VRcoeffe,%
\VRcoefff%
}$
The result is :


polynomialwould like to offer such an option, I cannot say, but it is clear he intended the arguments to be direct numbers and not macros. Perhaps you could email the author ofpolynomialif you are seeking something more official. – Steven B. Segletes Feb 15 '17 at 20:47