Diagonal line for a table with multiple rows

Question

Considering the answer of question, I used the slashbox package to draw a diagonal line. But the problem is I have multiple rows in my table and that makes the line not aligned well within the cell corners. It also gives wierd spaces between cells:

\documentclass{article}
\usepackage{slashbox}
\usepackage{adjustbox}

\begin{document}


\begin{table}[!htpc]
\begin{center}
  \centering
  \caption{some table.}
  \label{possibility}
  \begin{footnotesize}

   \adjustbox{max height=\dimexpr\textheight-5.5cm\relax,
           max width=\textwidth}{
\begin{tabular}{|c|c|c|c|c|c|c|c|c|}

  \hline
  % after \\: \hline or \cline{col1-col2} \cline{col3-col4} ...
  &first  & first  & second  & second & both  & both  & &\\
  &key & key &  key &  key& key & key & none&all\\
\backslashbox{Room}{Date}  &at & at &  at &  at & at & at& & \\
   &d & p &  d & p & d & p & &\\ \hline
  $C_1$&Y & N & N & N & N & N & N &N \\ \hline

  \hline


\end{tabular}
}
\end{footnotesize}
\end{center}
\end{table}

\end{document}

EDIT

I have used the answer presented by @bernard but it gives me ! Use of \line doesn't match its definition as an error. Not sure if it would happen for others as well.

Bernard · Answer 1 · 2017-05-16T09:54:37.123

2

It's better to use diagbox, which is more powerful. I improved your table using makecell (allows for line breaks and vertical padding in cells). Also, don't use the center environment in tables, as it adds unwanted vertical spacing; use \centering instead. The placement of the diagonal line is adjusted through the optional argument of \multirow.

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{diagbox}
\usepackage{adjustbox}
\usepackage{caption, multirow, makecell}
\setcellgapes{3pt}

\begin{document}

\begin{table}[!htp]
  \centering
  \caption{some table.}
  \label{possibility}
  \footnotesize\makegapedcells
   \adjustbox{max height=\dimexpr\textheight-5.5cm\relax,
   max width=\textwidth}{
  \begin{tabular}{|*{9}{c|}}
    \hline
    \multirowcell{5.2}[2.3ex]{\diagbox[height=5.17\line]{\rlap{\enspace\raisebox{2ex}{Room}}}{\raisebox{-3.5ex}{Date}}} &\makecell{first\\key} & \makecell{first\\key} & \makecell{second\\key} & \makecell{second\\key} & \makecell{both\\keys} & \makecell{both\\keys}& none&all\\
          & at & at & at & at & at & at & & \\
          & d & p & d & p & d & p & & \\ \hline
    $C₁$ & Y & N & N & N & N & N & N & N \\
    \hline
  \end{tabular}
  }
\end{table}

\end{document}

edited May 16 '17 at 09:54

answered May 16 '17 at 09:02

Bernard

271,350

Always vote +1 for my friends. – Sebastiano May 16 '17 at 09:02
Why did you comment out the adjustbox? – lonesome May 16 '17 at 09:43
@lonesome: Sorry. I did it to see whether the table overflowed the prescribed dimensions, and I forgot to uncomment before posting. – Bernard May 16 '17 at 09:50
It also gives error as ! Use of \line doesn't match its definition. – lonesome May 16 '17 at 09:50
I asked about adjustbox just in case if it was a wrong choice. – lonesome May 16 '17 at 09:51
I have no idea, because I never used it for tables (it can result in unreadable text within table), and here it doesn't seem to be useful. As to the error you mention, I don't have it. I only had a warning about an overfull vbox, due to the value of the no of rows in \multirow, solved by changing 4 to 5.2. – Bernard May 16 '17 at 10:00
any other unit to use for defining the height of dialogbox? – lonesome May 16 '17 at 10:11
Any unit you please. \line is supposed to be the interrow spacing in the table. For vertical spacings I would suggest ex, as the number of these should not change much if you decide to change the document font size (ideally, should not change at all). – Bernard May 16 '17 at 10:23
so can you replace [height=5.17\line] with something to act similarly? should I just use 5.17 as the length? – lonesome May 16 '17 at 10:42
Absolutely. Anyway, I had a rough estimate of the value, and it was adjusted by trial and error. – Bernard May 16 '17 at 10:43
but it still gives this error when I remove \line that the pt is inserted as a unit which is wrong. More precisely:! Illegal unit of measure (pt inserted). – lonesome May 16 '17 at 10:56
Let us continue this discussion in chat. – Bernard May 16 '17 at 11:16
still same error for \line even I just copy pasted the entire code of yours. – lonesome May 17 '17 at 02:21
@lonesome: Do you have the last version (2.2) of diagbox? It might be a possibility. – Bernard May 17 '17 at 08:04
@Bernard Well, how to find out if the version is 2.2 or not? – lonesome Jun 02 '17 at 03:14
@lonesome: You should find the version in the .log file. I obtain this line on my system: Package: diagbox 2016/12/28 v2.2 Making table heads with diagonal lines. Other than that, [height=14ex] is fine for me. – Bernard Jun 02 '17 at 08:00
aaaa. mine is v2. – lonesome Jun 02 '17 at 10:31
Well, you should update, anyway. – Bernard Jun 02 '17 at 10:55

score 0 · Answer 2 · answered Oct 17 '21 at 10:33

Here is what you can do with {NiceTabular} of nicematrix.

\documentclass{article}
\usepackage{geometry}
\usepackage{caption}
\usepackage{nicematrix}
\begin{document}
\begin{table}[!htp]
  \centering
  \caption{some table.}
  \label{possibility}
  \begin{NiceTabular}{w{c}{2cm}*{8}{c}}[vlines,cell-space-limits=3pt]
    \hline
    \Block{3-1}{\diagbox{\quad \rule[-5pt]{0pt}{5pt}Room}{\rule{0pt}{15pt}Date\quad}}
    & \Block{}{first\key}  & \Block{}{first\key} 
    & \Block{}{second\key} & \Block{}{second\key} 
    & \Block{}{both\keys}  & \Block{}{both\keys}& none&all\
          & at & at & at & at & at & at & & \
          & d & p & d & p & d & p & & \ \hline
    $C_1$ & Y & N & N & N & N & N & N & N \
    \hline
  \end{NiceTabular}
\end{table}
\end{document}

You need several compilations (because nicematrix uses PGF/Tikz nodes under the hood).

Diagonal line for a table with multiple rows

2 Answers2