How to draw tournament digraph with tkz-graph?

Question

Please, I want to draw a tournament digraph of order n (n=6 as example) with tikz. But i don't know how i can exclude the repeated vertex in the seconde loop. There is my code:

\documentclass{article}
\usepackage{tikz}
\usepackage{tkz-graph}
\usetikzlibrary{graphs,graphs.standard}

    \begin{document}
            \begin{tikzpicture}
            \SetGraphUnit{2}
            \renewcommand*{\VertexLineColor}{white}
            \renewcommand*{\VertexLightFillColor}{red}
            \renewcommand*{\VertexLineWidth}{1pt}
            \GraphInit[vstyle=Welsh]
            \Vertices{circle}{1,2,3,4,5,6}
            \AddVertexColor{blue}{5,1}
            \SetUpEdge[style={->,very thick},color=red]
            \foreach \v in {1,...,5}{
              \foreach \vv in {\v,...,6}{\Edge(\v)(\vv)};  
            };

        \end{tikzpicture}
    \end{document}

please extend your code snippet to complete small document beginning with \documentclass{...} and end with \end{document}. As it is, it gives errors (undefined control sequence ...). Welcome to TeX.SE! — Zarko, May 18 '17 at 17:38
I took liberty and instead you edit your question (complete code snippet and correct question title and text. You image is drawn with tkz-graph (which is based on tikz) . Next time this you should do yourself ... — Zarko, May 18 '17 at 18:59

Zarko · Answer 1 · 2017-05-18T23:06:05.917

\documentclass{article} 
\usepackage{tkz-graph} 
\usetikzlibrary{arrows.meta}

\begin{document}
    \begin{tikzpicture}
    \SetGraphUnit{2}
    \renewcommand*{\VertexLineColor}{white}
    \renewcommand*{\VertexLightFillColor}{red}
    \renewcommand*{\VertexLineWidth}{1pt}
    \GraphInit[vstyle=Welsh]
    \Vertices{circle}{1,2,3,4,5,6}
    \AddVertexColor{blue}{5,1}
    \SetUpEdge[style={-{Straight Barb[length=1mm,width=1.2mm]}, thick},color=red]
     \foreach \v [count=\vi from 2] in {1,...,5}{
     \foreach \vv in {\vi,...,6}{\Edge(\v)(\vv)};      
     }; 
\end{tikzpicture}    
\end{document}

gives:

Addendum: Solution for your request in one of your comment:

\documentclass{article}
\usepackage{tkz-graph}
\usetikzlibrary{arrows.meta}


\begin{document}
    \begin{tikzpicture}
    \SetGraphUnit{2}
    \renewcommand*{\VertexLineColor}{white}
    \renewcommand*{\VertexLightFillColor}{red}
    \renewcommand*{\VertexLineWidth}{1pt}
    \GraphInit[vstyle=Welsh]
    \SetVertexNoLabel % <-- added
    \Vertices{circle}{1,2,3,4,5,6}
    \SetUpEdge[style={-{Straight Barb[length=1mm,width=1.2mm]}, thick},color=red]
     \foreach \v [count=\vi from 2] in {1,...,5}
     {
     \foreach \vv in {\vi,...,6}{\Edge(\v)(\vv)};
     };
     \SetVertexLabel
    \Vertices{circle}{A,B,C,D,E,F} % <-- added
    \AddVertexColor{blue}{1,5}% <-- moved here
\end{tikzpicture}
\end{document}

Addendum (2): solution for naming of vertices without their double drawing:

\documentclass{article}
\usepackage{tkz-graph}
\usetikzlibrary{arrows.meta}

\begin{document}
    \begin{tikzpicture}
\SetGraphUnit{2}
\renewcommand*{\VertexLineColor}{white}
\renewcommand*{\VertexLightFillColor}{red}
\renewcommand*{\VertexLineWidth}{1pt}
\GraphInit[vstyle=Welsh]
\Vertices{circle}{A,B,C,D,E,F}
\SetUpEdge[style={-{Straight Barb[length=1mm,width=1.2mm]}, thick},color=red]
 \foreach \v [remember=\v as \vi (initially A)] in {B,...,F}
 {
 \foreach \vv in {\v,...,F}{\Edge(\vi)(\vv)};
 };
\AddVertexColor{blue}{A,E}
    \end{tikzpicture}
\end{document}

@marsupilam, ups, I forgot to move \AddVertexColor{blue}{1,5} on the place after \Vertices{circle}{A,B,C,D,E,F}. Corected. Thank you very much for notice. — Zarko, May 18 '17 at 21:45
Sorry deleted my comment after your fix, even though it is worth explaining you place the vertices twice : First for joining, then again for labeling (because tkz-graph doesn' t seem to allow for labeling separately from node-naming). — marsupilam, May 18 '17 at 21:51
@marsupilam, unfortunately I don't speak French, so the manual for tkz-graph is quite cryptic to me. I search in it for possibilities for labeling nodes independent to nodes' names but there is no example, which I could understand. To solve this problem in side drawing of edges drawing: temporary I didn't manage to make counter \vi as alphabetic. — Zarko, May 18 '17 at 21:59
too bad for the french, as the tkz-graph manual is entirely written in fully prosodic rhymed alexandrin verses. (More seriously, I think I remember there is some way to TeX-hackishly shift[by a constant-addititive-translation] a character code to another, possibly pushing A to 1 or the other way around... ?) — marsupilam, May 18 '17 at 22:17
@marsupilam, meanwhile I prepare new solution which the problem of vertices naming is solved in loops for drawing edges. Now the counters in loops are alphabetic and double drawing of vertices is not necessary anymore. — Zarko, May 18 '17 at 23:08

marsupilam · Accepted Answer · 2017-05-18T20:53:28.780

Use the \ifthenelse construction.

The output

The code

\documentclass[12pt,tikz]{standalone}
\usepackage{tkz-graph}
\begin{document}
\begin{tikzpicture}
  \SetGraphUnit{2}
  \renewcommand*{\VertexLineColor}{white}
  \renewcommand*{\VertexLightFillColor}{red}
  \renewcommand*{\VertexLineWidth}{1pt}
  \GraphInit[vstyle=Welsh]
  \Vertices{circle}{1,2,3,4,5,6}
  \AddVertexColor{blue}{5,1}
  \SetUpEdge[style={->,very thick},color=red]
  \foreach \v in {1,...,5}
  {
    \foreach \vv in {\v,...,6}
    {
      \ifthenelse{\v=\vv}%
      {}% the empty `then` clause
      {%
        \Edge(\v)(\vv)% the `else` clause
      }  
    }
  }
\end{tikzpicture}
\end{document}

Per request

With french names for variables, as a token of appreciation to Alain's mysterious tkz-graph manual.

\documentclass[12pt,tikz]{standalone}
\usepackage{tkz-graph}
\begin{document}
\begin{tikzpicture}
  \SetGraphUnit{2}
  \renewcommand*{\VertexLineColor}{white}
  \renewcommand*{\VertexLightFillColor}{red}
  \renewcommand*{\VertexLineWidth}{1pt}
  \GraphInit[vstyle=Welsh]
  \Vertices{circle}{A,B,C,D,E,F}
  \AddVertexColor{blue}{E,A}
  \SetUpEdge[style={->,very thick},color=red]
  \foreach \lettre/\nombre in {A/1,B/2,C/3,D/4,E/5}
  {
    \foreach \llettre/\nnombre in {A/1,B/2,C/3,D/4,E/5,F/6}
    {
      \ifthenelse{\nombre<\nnombre}
      {%
        \Edge(\lettre)(\llettre)
      }  
      {}
    }
  }
\end{tikzpicture}
\end{document}

interesting solution (1). instead ifthenelse you can use { \ifnum\v=\vv\else\Edge(\v)(\vv)\fi} — Zarko, May 18 '17 at 19:29
@Zarko Thank you. Indeed looks more fundamental. I'm really not familiar with (also intimidated by) pure LaTeX (TeX ?) logic. — marsupilam, May 18 '17 at 19:49
@HTeX, you are welcome, but here is habit (policy) that instead say "thank you" (what is fine, of course) rather up-vote answer and accept one, which the best fit your requirements :) — Zarko, May 19 '17 at 18:52

score 1 · Answer 3 · answered May 18 '17 at 19:04

1

Another way, same output.

\documentclass[12pt,tikz]{standalone}
\usepackage{tkz-graph}
\begin{document}
\begin{tikzpicture}
  \SetGraphUnit{2}
  \renewcommand*{\VertexLineColor}{white}
  \renewcommand*{\VertexLightFillColor}{red}
  \renewcommand*{\VertexLineWidth}{1pt}
  \GraphInit[vstyle=Welsh]
  \Vertices{circle}{1,2,3,4,5,6}
  \AddVertexColor{blue}{5,1}
  \SetUpEdge[style={->,very thick},color=red]
  \foreach \v in {1,...,5}
  {
    \foreach \vv in {\number\numexpr\v+1\relax,...,6}
    {
        \Edge(\v)(\vv)
    }
  }
\end{tikzpicture}
\end{document}

answered May 18 '17 at 19:04

marsupilam

6,383

I saw this construction some days ago, and Zarko's answer made me think of it. – marsupilam May 18 '17 at 19:45
Thank's a lot for you Zarko and Marsupilam ! what about if i put an alphabetical vertices name set indeed of numerical. ie \Vertices{circle}{A,B,C,D,E,F} – HTeX May 18 '17 at 20:22
@HTeX see my other answer for edited version. – marsupilam May 18 '17 at 20:54

How to draw tournament digraph with tkz-graph?

3 Answers3

The output

The code

Per request