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I wanna to write 2 sigmas with lower and upper bound but I don't know how ?

\documentclass{amsart}[12pt]

\usepackage{amsmath, amsthm, amscd, amssymb, amsfonts}
\usepackage{environ}
\usepackage{mathtools}

\begin{document}

$$‎\sum^{N}_{n=0}{\sum_{m=1}^{(n+1)/2}\mu |c_n|\frac{n!}{(2m-1)!\pi ^{n-2m-2}‎
‎}|z|^{2m-1}‎}$$

\end{document}
Werner
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shabnam
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1 Answers1

2

You should to use \limits_{lower}^{upper} after \sum

\documentclass{amsart}[12pt]

\usepackage{amsmath, amsthm, amscd, amssymb, amsfonts}
\usepackage{environ} 
\usepackage{mathtools}

\begin{document}

\[
\sum\limits^{N}_{n=0}{\sum\limits_{m=1}^{(n+1)/2}\mu |c_n|\frac{n!}{(2m-1)!\pi ^{n-2m-2}‎ ‎}|z|^{2m-1}‎}
\]

\end{document}

enter image description here

sergiokapone
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    How does this output differ from OP's output? Within display mode, isn't \sum already with \limits by default? – Teepeemm Oct 23 '17 at 19:11
  • @Teepeemm I think before the question was edited by Werner, the formula was enclosed in one sign $, but now I think, it does not matter. – sergiokapone Oct 24 '17 at 17:11