I'm unable prevent block 6 from overlapping block 3. Why?
\documentclass[x11names, landscape]{article}
%\documentclass[a4paper]{article}
\usepackage{tikz}
\usetikzlibrary{shapes,arrows,chains,calc}
%%%<
\usepackage{verbatim}
\usepackage[active,tightpage]{preview}
\usetikzlibrary{intersections}
\usepackage[utf8]{inputenc} %----permette l' uso dei caratteri accentati
\usepackage[italian]{babel} %-----permette la sillabazione secondo le regole italiane
\PreviewEnvironment{tikzpicture}
\setlength\PreviewBorder{115mm}% %%%>
\begin{document}
\tikzstyle{block1} = [rectangle, rounded corners, minimum width=3cm, minimum height=1cm, text centered, draw, fill=blue!20, text width=6cm]
\tikzstyle{block2} = [rectangle, rounded corners, minimum width=3cm, minimum height=1cm, text centered, draw, fill=blue!20, text width=3cm]
\tikzstyle{decision} = [diamond, minimum width=3cm, minimum height=1cm, text centered, draw, fill=blue!20, text width=2cm]
\tikzstyle{line} = [draw, -latex']
\begin{tikzpicture}[node distance = 2cm, auto]
% Place nodes
\node [block1] (1) {\textbf{\small Presentazione Istanza}};
\node [block2, below of=1] (2) {Avvio procedimento (comunicazione responsabile)};
\node [block2, below of=2] (3) {verifica documentazione};
\node [block1, right of=3, distance=8 cm] (6) {Istruttoria};
\node [block2, below of=3] (4) {irricevibilità con possibilità di integrazione};
\node [decision, below of=4] (5) {Integrazione effettuata};
\node [decision, below of=6] (7) {soggetto a parere della commissione};
% Draw edges
% \path [line] (1) -| (4);
% \path [line] (1) -- (3);
% \path [line] (3.west) node [, above,color=black] {NO} |-
(5);
%($(5.east));
% \path [line] (3.south) node [right,below,color=black] {SI} |-
(9.east);
% \path [line] (4.east) node [right,below,color=black] {SI} -|
(8.east);
%($(9.east)+(30mm,0) );
% \path [line] (4.east) node [right, above,color=black] {SI} -| ($(9.east)+(1em,0)$) -- (9.east);
%\path [line] (6.west) node [left, above,color=black] {NO} -| ($(9.west)+(-2em,0)$) -- (9.west);
% \path [line] (4)-> node [left, ,color=black] {NO} (5);
% \path [line] (5) -> (6);
% \path [line] (6) -- node [left, ,color=black] {SI} (8);
%\path [line] (7) -- (8);
% \path [line] (8) -- (9);
% Find the intersection of the two paths. %\path [name intersections={of=4to12 and 6to14}];
%\coordinate (S) at (intersection-1);
% Define a circle around this intersection for the arc.
%\path[name path=circle] (S) circle(2mm);
% Find the intersections of second line and circle.
% \path [name intersections={of=circle and 6to14}];
%\coordinate (I1) at (intersection-1);
%\coordinate (I2) at (intersection-2);
% Draw normal line segments, except for portion within circle.
%\draw (6) -- (I2);
%\draw[->] (I1) -| ([xshift=2cm, yshift=0cm]6.east) |- (14);
% Draw arc at intersection
%\draw () arc (180:0:2mm);
\end{tikzpicture}
\end{document}


node distance, notdistance, but have a look at Difference between "right of=" and "right=of" in PGF/TikZ – Torbjørn T. Feb 06 '18 at 10:43\node [block1, right of=3, distance=8 cm] (6) {Istruttoria};, which should have been\node [block1, right of=3, node distance=8 cm] (6) {Istruttoria};, but see my answer. – Torbjørn T. Feb 06 '18 at 11:00