Drawing parallelogram and circle in latex

Question

I want to draw a Parallelogram which there is a line perpendicular to it and also there are some circles on this Parallelogram and some points on the circles. as you can see in this picture. could any body tell me how I can do that in latex?

Welcome to Latex.SX. Try to provide a minimal compilable working example. Do circles look like circles or like ellipses for perspective vision ? — Tarass, Mar 17 '18 at 16:32
welcome to tex.se! what you try so far? for an similar picture? o you look to http://www.texample.net/tikz/examples/ — Zarko, Mar 17 '18 at 16:34

score 7 · Answer 1 · answered Mar 17 '18 at 16:45

7

I am wondering about the same thing as @Tarass. Here are both possibilities, a picture according to your description and a 3D picture.

\documentclass{article}
\usepackage{tikz}
\usepackage{tikz-3dplot}
\tdplotsetmaincoords{110}{20}
\usepackage{subfig}
\begin{document}
\begin{figure}
 \subfloat{\begin{tikzpicture}
 \draw (-4,-2) -- (2,-2,0) -- (4,2,0) -- (-2,2,0) -- cycle;
 \draw (0,0) circle ({2/3});
 \draw (0,0) circle ({4/3});
 \foreach \Angle in {45,135,225,315}
 {\draw[fill] ({\Angle-30}:{2/3}) circle (1pt);
 \draw[fill] ({\Angle+15}:{4/3}) circle (1pt);}
 \draw (0,0) -- (0,3);
\end{tikzpicture}}
\subfloat{\begin{tikzpicture}
 \tdplotsetrotatedcoords{90}{0}{0}
 \begin{scope}[tdplot_rotated_coords]
 \draw (0,0,0) circle ({2/3});
 \draw (0,0,0) circle ({4/3});
 \foreach \Angle in {45,135,225,315}
 {\draw[fill] ({\Angle-45}:{2/3}) circle (1pt);
 \draw[fill] (\Angle:{4/3}) circle (1pt);}
 \draw (-2,-2,0) -- (2,-2,0) -- (2,2,0) -- (-2,2,0) -- cycle;
 \draw (0,0,0) -- (0,0,3);
 \end{scope}
\end{tikzpicture}}
\end{figure}
\end{document}

answered Mar 17 '18 at 16:45

You were faster ... – Tarass Mar 17 '18 at 16:54
@Tarass No worries, I upvoted your post as well. ;-) – Mar 17 '18 at 17:25
You had time to do this too !!! – Tarass Mar 17 '18 at 17:28
@Tarass Not really, I am still busy with this and that. – Mar 17 '18 at 17:31
That shall never pass throught this !! – Tarass Mar 17 '18 at 17:33
@Tarass Sorry, the language barrier. (I'll decouple now, have fun with the next questions ;-) – Mar 17 '18 at 17:36
The bird never pass the door. – Tarass Mar 17 '18 at 18:23
@Tarass I see ;-) I think it's just a matter of perspective ;-) – Mar 17 '18 at 21:27

score 6 · Answer 2 · answered Mar 17 '18 at 16:52

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{3d}
\begin{document}

\begin{tikzpicture}[x  = {(1cm,0cm)},
                    y  = {(40:.5cm)},
                    z  = {(0cm,1cm)}]
\begin{scope}[canvas is xy plane at z=0]
  \draw (0,0) circle (3) ;
  \draw (0,0) circle (2) ;
  \draw (-5,-4) -- (5,-4) -- (5,4) -- (-5,4) -- cycle ;

  \foreach \x in {30,60,...,360} {\fill (\x:3) circle (2pt) ;} ;
\end{scope}

\begin{scope}[canvas is xz plane at y=0]
  \draw[-stealth] (0,0)--(0,4) ;
\end{scope}
\end{tikzpicture}

\bigskip

\begin{tikzpicture}

  \draw (0,0) circle (1) ;
  \draw (0,0) circle (.5) ;

  \draw (-7,-2) -- (2.5,-2) -- (7,1.5) -- (-2.5,1.5) -- cycle ;
  \draw[-stealth] (0,0)--(0,4) ;
  \foreach \x in {30,60,...,360} {\fill (\x:1) circle (2pt) ;} ;

\end{tikzpicture}

\end{document}

Drawing parallelogram and circle in latex

2 Answers2