Circuitikz problem getting inductor

Question

I have troubles obtaining the right shape of an inductor using circuitikz. I am getting a black filled rectangle instead :

Here is my MWE :

\documentclass{article}

\usepackage{circuitikz}
\usepackage[french]{babel}

\begin{document}

\begin{circuitikz}
\draw (0,0)to[european inductor](2,0);
\draw(0,0)to(0,-.25)to[ground](0,-.5);
\end{circuitikz}

\end{document}

I am using Windows 7 and MiKTeX 2.9, which I just updated. Thank you.

I missed the fact that the european inductor is indeed correct. It seems like the true issue is with cute inductor, or simply L : I get the following error message :

! Undefined control sequence.
\pgf@sh@bg@cuteinductorshape ...mationadjustments
\par \pgfmathsetlength {\p...
l.8 \draw (0,0) to [L] (2,0)
;
The control sequence at the end of the top line
of your error message was never \def'ed. If you have
misspelled it (e.g., `\hobx'), type `I' and the correct
spelling (e.g., `I\hbox'). Otherwise just continue,
and I'll forget about whatever was undefined. 

I suspect there is a connection with this question : Miktex 2.9 pgfplots, circuitikz...

Answer 1

• you should add tikz library babel (it remove changes introduced by french babel in tikz code)
• ground is node

\documentclass{article}

\usepackage[french]{babel}
\usepackage{circuitikz}
\usetikzlibrary{babel}

\begin{document}
    \begin{circuitikz}
\draw   (0,0) to [european inductor] (2,0)
        (0,0) -- (0,-0.25) node [ground] {};
    \end{circuitikz}
\end{document}

edit: with use L for inductor:

\documentclass{article}

\usepackage[french]{babel}
\usepackage{circuitikz}
\usetikzlibrary{babel}

\begin{document}
    \begin{circuitikz}
\draw   (0,0) to [L] (2,0)
        (0,0) -- (0,-0.25) node [ground] {};
    \end{circuitikz}
\end{document}