\documentclass[border=15pt,pstricks,12pt]{standalone}
\usepackage{pst-eucl}
\begin{document}
\begin{pspicture}[showgrid](-5,-5)(10,10)
\psset{unit=2cm,PointSymbol=none,PointName=none}
\pstTriangle(0,4){C}(0,0){A}(3,0){B}
%%% OR \pstTriangle[PointSymbol=none](0,4){C}(0,0){A}(3,0){B}
\pstMiddleAB{A}{B}{I1} \pstArcOAB{I1}{A}{B}
\pstMiddleAB{B}{C}{I2} \pstArcOAB{I2}{B}{C}
\pstMiddleAB{C}{A}{I3} \pstArcOAB{I3}{C}{A}
\end{pspicture}
\end{document}
\documentclass[border=15pt,pstricks,12pt]{standalone}
\usepackage{pst-eucl}
\begin{document}
\begin{pspicture}[showgrid](-2,-2)(2,2)
\pstTriangle[PointSymbol=none,%% <<---
linecolor=blue,linewidth=1.5\pslinewidth](1.5,-1){A}(0,1){B}(-1,-.5){C}
\pstTriangleIC[linecolor=red]{A}{B}{C}
\pstTriangleOC[linecolor=red]{A}{B}{C}
\end{pspicture}
\end{document}
\documentclass[border=15pt,pstricks,12pt]{standalone}
\usepackage{pst-eucl}
\begin{document}
\begin{pspicture}[showgrid](-2,-2)(2,2)
\pstGeonode[PointSymbol=none,PosAngle={0,90,180}](1.5,-1){A}(0,1){B}(-1,-.5){C}
\pspolygon[linejoin=2](A)(B)(C)
\pstTriangleIC[linecolor=red]{A}{B}{C}
\pstTriangleOC[linecolor=red]{A}{B}{C}
\end{pspicture}
\end{document}
A new problem.
\documentclass[border=15pt,pstricks,12pt]{standalone}
\usepackage{pst-eucl}
\begin{document}
\psset{unit=3cm}
\begin{pspicture}(2,2)
%{\psset{PointSymbolA=none,PointSymbolB=none,PointName=none}
{
\psset{PointSymbol=none,PointName=none}
\pstGeonode(0,0){A}(1,0){B}(1,1){C}(0,1){D}
\pswedge[fillstyle=solid,fillcolor=red](C){1}{135}{-45}
\pstTranslation{D}{B}{C}[C1] % phep tinh tien
\pstTranslation{B}{D}{C}[C2]
\pstInterLC{C1}{C2}{C}{B}{M1}{M2} % giao diem duong tron va duong thang
\pstInterLC{A}{C1}{A}{M1}{M3}{M4}
\pstInterLC{A}{C2}{A}{M2}{M5}{M6}
%\psGetDistanceAB(A)(M2){MW} get 1.73205
\psarc(A){1.73205}{0}{90}
\psline(M6)(A)(M4)
}
\psdot*(1,1)
\end{pspicture}
\end{document}
\documentclass[border=15pt,pstricks,12pt]{standalone}
\usepackage{pst-eucl}
\begin{document}
\begin{pspicture}[showgrid](-5,-5)(10,10)
\pstGeonode[PointSymbol=none,PointName={B,C,none},PosAngle={-110,-80}](0,0){B}(7,0){C}(-1,0){Z}(5,0){Y}
\pstInterCC[PointSymbol=none,PosAngleA=90]{B}{Y}{C}{Z}{A}{M2} %%<<<---
\pspolygon(B)(A)(C)
\end{pspicture}
\end{document}
With ver 1.61 it produces:
With ver 1.63 it produces:










pst-eucldocumentation shows the same problem. Looks like a bug? – Sigur Jan 26 '19 at 15:47noneto each point:\pstTriangle[PointSymbolC=none,PointSymbolA=none,PointSymbolB=none](0,4){C}(0,0){A}(3,0){B}– Sigur Jan 26 '19 at 15:50PointSymbol=none,PointSymbolA=nonebut I don't know why. Maybe, as I said, a bug. – Sigur Jan 26 '19 at 16:16PosAngle={...,...,...}: I tried reproduce the figure using\psGeonode, then\pspolygon(A)(B)(C). No dot until I usePosAngle. – Bernard Jan 26 '19 at 16:57PosAngle, and didn't have it wthout this key. Now I don't have it anymore, like you. Perhaps there was some typo in my initial code, which has been removed unadvertently since then… – Bernard Jan 27 '19 at 00:45PointSymbolA=none. And it makes no difference if your first point is named C – Jan 27 '19 at 07:01