Matrix with uneven element lengths with added rows/columns

Question

Using the following code

\documentclass{beamer}
\beamertemplatenavigationsymbolsempty
\usepackage{verbatim}
\usepackage{tikz}
\usetikzlibrary{arrows, calc, fit, matrix}
\begin{document}
\tikzset{matrix rows/.initial=5,matrix cols/.initial=6,matrix name/.initial=x,
vline/.style={/utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix rows}}
{\ifnum\XX=1
\xdef\MatLstA{(\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
\xdef\MatLstB{(\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
\else
\xdef\MatLstA{\MatLstA (\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
\xdef\MatLstB{\MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
\fi},
insert path={node[fit=\MatLstA,inner sep=0pt] (fitA) {}
node[fit=\MatLstB,inner sep=0pt] (fitB) {}
($(fitA.east)!0.5!(fitB.west)$) coordinate (aux) 
(\pgfkeysvalueof{/tikz/matrix name}.north-|aux) -- (\pgfkeysvalueof{/tikz/matrix name}.south-|aux)}},%end vline
hline/.style={/utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix cols}}
{\ifnum\XX=1
\xdef\MatLstA{(\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
\xdef\MatLstB{(\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
\else
\xdef\MatLstA{\MatLstA (\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
\xdef\MatLstB{\MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
\fi},insert path={node[fit=\MatLstA,inner sep=0pt] (fitA) {}
node[fit=\MatLstB,inner sep=0pt] (fitB) {}
($(fitA.south)!0.5!(fitB.north)$) coordinate (aux) 
(\pgfkeysvalueof{/tikz/matrix name}.west|-aux) -- (\pgfkeysvalueof{/tikz/matrix name}.east|-aux)}},%end hline
full matrix grid/.style={vline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1},
hline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix rows}-1},
insert path={(\pgfkeysvalueof{/tikz/matrix name}.south west) rectangle (\pgfkeysvalueof{/tikz/matrix name}.north east)}}
}
\begin{frame}[t,fragile]
\frametitle{}
\begin{tikzpicture}
\matrix (x) [matrix of nodes, row sep=10pt, column sep=10pt] {%
15.1 & 23.7 & 19.7 & 15.4 & 18.3 & 23.0 & y\\
17.4 & 18.6 & 12.9 & 20.320.320.3 & 13.7 & 21.45 & y\\
10.3 & 26.1 & 15.718.918.9 & 14.0 & 17.8 & 33.8 & y\\
23.2 & 12.9 & 29.8 & 18.3 & 14.2 & 20.8 & y\\
xx & xx & xx & xx & xx & xx & y\\
13.5 & 17.1 & 20.7 & 27.1 & 18.918.9 & 16.6 & y\\};
\draw<2->[ultra thick, blue, latex'-] (x-2-1) node [fill, red!40!white, circle, inner sep=8pt, opacity=.4]{} -- (x-4-5) node [fill, blue!40!white, circle, inner sep=8pt, opacity=.4]{};
% Node names: (<name of matrix>-<row>-<column>)
% \draw[vline/.list={1,...,5},hline/.list={1,...,4}] (\pgfkeysvalueof{/tikz/matrix name}.north west) rectangle 
%  (\pgfkeysvalueof{/tikz/matrix name}.south east); % 
\draw[matrix name=x,matrix cols=6,matrix rows=5,full matrix grid];% drawing the borders
\end{tikzpicture}
\end{frame}
\end{document}

When new rows/columns are added, no lines are drawn between the new and previous ones. How can this be fixed?

I tried re-adjusting

matrix rows/.initial=5,matrix cols/.initial=6

to

matrix rows/.initial=0,matrix cols/.initial=0

or to

matrix rows/.initial=10,matrix cols/.initial=10

but it did not work.

From the answers I got, the problem was not on this line; the problem was that I did not re-adjust the line

\draw[matrix name=x,matrix cols=6,matrix rows=5,full matrix grid];

to

\draw[matrix name=x,matrix cols=7,matrix rows=6,full matrix grid];

You have to understand the code in the preamble. If you already understand, it will not be difficult. — , Apr 15 '19 at 04:57
@JouleVMy programming knowledge is limited. Please if you have a solution to this problem tell me — Hany, Apr 15 '19 at 04:59
Off topic: if you want to ping people, you must write e.g. @Andrew As ... instead of @AndrewAs .... — , Apr 15 '19 at 05:01
@JouleV When I leave a space after the name, sometimes the name does not appear in the comment! — Hany, Apr 15 '19 at 05:03
@JouleV I tried re-adjusting
matrix rows/.initial=5,matrix cols/.initial=6 to

matrix rows/.initial=0,matrix cols/.initial=0 or to

matrix rows/.initial=10,matrix cols/.initial=10 but it did not work — Hany, Apr 15 '19 at 05:14
Look at my answer and Andrew's answer. In short, you changed the initial values of matrix rows, matrix cols, but you reset these values later in your command, that is why it does not work. — , Apr 15 '19 at 05:15

score 4 · Accepted Answer · answered Apr 15 '19 at 04:59

You need to change the line:

\draw[matrix name=x,matrix cols=6,matrix rows=5,full matrix grid];

to

\draw[matrix name=x,matrix cols=7,matrix rows=6,full matrix grid];

All that this line is doing is drawing a grid with the specified number of rows and columns. In this case, this produces:

Here is the full code:

documentclass{beamer}
\beamertemplatenavigationsymbolsempty
\usepackage{verbatim}
\usepackage{tikz}
\usetikzlibrary{arrows, calc, fit, matrix}
\begin{document}
\tikzset{matrix rows/.initial=5,matrix cols/.initial=6,matrix name/.initial=x,
vline/.style={/utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix rows}}
{\ifnum\XX=1
\xdef\MatLstA{(\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
\xdef\MatLstB{(\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
\else
\xdef\MatLstA{\MatLstA (\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
\xdef\MatLstB{\MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
\fi},
insert path={node[fit=\MatLstA,inner sep=0pt] (fitA) {}
node[fit=\MatLstB,inner sep=0pt] (fitB) {}
($(fitA.east)!0.5!(fitB.west)$) coordinate (aux)
(\pgfkeysvalueof{/tikz/matrix name}.north-|aux) -- (\pgfkeysvalueof{/tikz/matrix name}.south-|aux)}},%end vline
hline/.style={/utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix cols}}
{\ifnum\XX=1
\xdef\MatLstA{(\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
\xdef\MatLstB{(\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
\else
\xdef\MatLstA{\MatLstA (\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
\xdef\MatLstB{\MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
\fi},insert path={node[fit=\MatLstA,inner sep=0pt] (fitA) {}
node[fit=\MatLstB,inner sep=0pt] (fitB) {}
($(fitA.south)!0.5!(fitB.north)$) coordinate (aux)
(\pgfkeysvalueof{/tikz/matrix name}.west|-aux) -- (\pgfkeysvalueof{/tikz/matrix name}.east|-aux)}},%end hline
full matrix grid/.style={vline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1},
hline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix rows}-1},
insert path={(\pgfkeysvalueof{/tikz/matrix name}.south west) rectangle (\pgfkeysvalueof{/tikz/matrix name}.north east)}}
}
\begin{frame}[t,fragile]
\frametitle{}
\begin{tikzpicture}
\matrix (x) [matrix of nodes, row sep=10pt, column sep=10pt] {%
15.1 & 23.7 & 19.7 & 15.4 & 18.3 & 23.0 & y\\
17.4 & 18.6 & 12.9 & 20.320.320.3 & 13.7 & 21.45 & y\\
10.3 & 26.1 & 15.718.918.9 & 14.0 & 17.8 & 33.8 & y\\
23.2 & 12.9 & 29.8 & 18.3 & 14.2 & 20.8 & y\\
xx & xx & xx & xx & xx & xx & y\\
13.5 & 17.1 & 20.7 & 27.1 & 18.918.9 & 16.6 & y\\};
\draw<2->[ultra thick, blue, latex'-] (x-2-1) node [fill, red!40!white, circle, inner sep=8pt, opacity=.4]{} -- (x-4-5) node [fill, blue!40!white, circle, inner sep=8pt, opacity=.4]{};
% Node names: (<name of matrix>-<row>-<column>)
% \draw[vline/.list={1,...,5},hline/.list={1,...,4}] (\pgfkeysvalueof{/tikz/matrix name}.north west) rectangle
%  (\pgfkeysvalueof{/tikz/matrix name}.south east); %
\draw[matrix name=x,matrix cols=7,matrix rows=6,full matrix grid];% drawing the borders
\end{tikzpicture}
\end{frame}
\end{document}

score 3 · Answer 2 · 2019-04-15T05:12:40.000

Andrew has pointed out the right thing. Now let me dig into it. This is the \tikzset, aligned (in my favorite way)

\tikzset{
    matrix rows/.initial=5,
    matrix cols/.initial=6,
    matrix name/.initial=x,
    vline/.style={
        /utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix rows}} {
            \ifnum\XX=1
                \xdef\MatLstA{
                    (\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
                \xdef\MatLstB{
                    (\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
            \else
                \xdef\MatLstA{
                    \MatLstA (\pgfkeysvalueof{/tikz/matrix name}-\XX-#1)}
                \xdef\MatLstB{
                    \MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\XX-\the\numexpr1+#1\relax)}
            \fi},
        insert path={
            node[fit=\MatLstA,inner sep=0pt] (fitA) {}
            node[fit=\MatLstB,inner sep=0pt] (fitB) {} ($(fitA.east)!0.5!(fitB.west)$) coordinate (aux) 
            (\pgfkeysvalueof{/tikz/matrix name}.north-|aux) -- (\pgfkeysvalueof{/tikz/matrix name}.south-|aux)}
    },%end vline
    hline/.style={
        /utils/exec=\foreach \XX in {1,...,\pgfkeysvalueof{/tikz/matrix cols}} {
            \ifnum\XX=1
                \xdef\MatLstA{
                    (\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
                \xdef\MatLstB{
                    (\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
            \else
                \xdef\MatLstA{
                    \MatLstA (\pgfkeysvalueof{/tikz/matrix name}-#1-\XX)}
                \xdef\MatLstB{
                    \MatLstB (\pgfkeysvalueof{/tikz/matrix name}-\the\numexpr1+#1\relax-\XX)}
            \fi},
        insert path={
            node[fit=\MatLstA,inner sep=0pt] (fitA) {}
            node[fit=\MatLstB,inner sep=0pt] (fitB) {} ($(fitA.south)!0.5!(fitB.north)$) coordinate (aux) 
            (\pgfkeysvalueof{/tikz/matrix name}.west|-aux) -- (\pgfkeysvalueof{/tikz/matrix name}.east|-aux)}
    },%end hline
    full matrix grid/.style={
        vline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1},
        hline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix rows}-1},
        insert path={(\pgfkeysvalueof{/tikz/matrix name}.south west) rectangle (\pgfkeysvalueof{/tikz/matrix name}.north east)}
    }
}

Without any knowledge in advance, I think we can still understand vline style will add vertical lines in a given list, and hline for horizontal lines.

Now, look at full matrix grid:

full matrix grid/.style={
    vline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1},
    hline/.list={1,...,\the\numexpr\pgfkeysvalueof{/tikz/matrix rows}-1},
    insert path={(\pgfkeysvalueof{/tikz/matrix name}.south west) rectangle (\pgfkeysvalueof{/tikz/matrix name}.north east)}
}

It outputs a set of hlines and vlines, in a given list. The list is controled by matrix cols and matrix rows (\the\numexpr\pgfkeysvalueof{/tikz/matrix cols}-1, etc.), so you have to change the values of these options to change the grid.

The initial value of matrix rows and matrix cols are 5 and 6, but that doesn't matter, because you already reset it again in the command

\draw[matrix name=x,matrix cols=6,matrix rows=5,full matrix grid];

Now, change the value of matrix cols and matrix rows in the above command, you will get what you want.

For the sake of completeness, see the compilable code in Andrew's answer.

Thank you all very much, I got it. and it works fine. By the way, I put @JouleV with a space after it, before Thank you, and it did not show — Hany, Apr 15 '19 at 05:22
@Hany It is off topic here, but you can find out more how @ in comments work by reading this question. — , Apr 15 '19 at 16:12

Matrix with uneven element lengths with added rows/columns

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