The following works fine,
\begin{equation*}
\begin{aligned}
\begin{split}
\left\| \left(a - c\right) - \frac{|b|^2\cdot |d|^2}{|b \times d|^2} \left[
\left(\left(a - c\right)\cdot \left(\frac{b}{|b|} - \frac{b \cdot d}{|b|\cdot|d|} \cdot \frac{d}{|d|}\right)\right) \cdot \frac{b}{b} \right.\right. + \\
\left.\left. \left(\left(a - c\right)\cdot \left(\frac{d}{|d|} - \frac{b \cdot d}{|b|\cdot|d|} \cdot \frac{b}{|b|}\right)\right) \cdot \frac{d}{d}
\right] \right\| = \frac{|(a - c) \cdot b \times d|}{|b \times d|}
\end{split}
\end{aligned}
\end{equation*}
but if I add &, it throws an error
\begin{equation*}
\begin{aligned}
\begin{split}
\left\| \left(a - c\right) - \frac{|b|^2\cdot |d|^2}{|b \times d|^2} \left[
& \left(\left(a - c\right)\cdot \left(\frac{b}{|b|} - \frac{b \cdot d}{|b|\cdot|d|} \cdot \frac{d}{|d|}\right)\right) \cdot \frac{b}{b} \right.\right. + \\
& \left.\left. \left(\left(a - c\right)\cdot \left(\frac{d}{|d|} - \frac{b \cdot d}{|b|\cdot|d|} \cdot \frac{b}{|b|}\right)\right) \cdot \frac{d}{d}
\right] \right\| = \frac{|(a - c) \cdot b \times d|}{|b \times d|}
\end{split}
\end{aligned}
\end{equation*}
According to many posts, I tried several combinations of \begin{equation*}, \begin{aligned}, \begin{split} and \begin{multline*}
but without success. What do I miss?
Expected result
(Without & the first square bracket is also ok, but the alignment is destroyed)
Comment, why this is not a duplicate of other questions: To me, the crucial point of the answer is, that you need an extra \vphantom{\frac{b}{b}}\right.\right. and you have to add another & \left.\left. line.



&between\leftand\right. – campa Apr 26 '19 at 12:26