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I am still new in latex...I have tried many times to write this equation in latex, but no way...always error...any help, please.

My Regards.

Equation

Denis
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Qusay
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    Yes, you can. And it is written in Tex, you know it and so do I. So put yourself to work and come back when you have something to show! Minimum effort is requiered in order to receive answers. – Stephen Sep 30 '19 at 07:27
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    Did you hear about mathmode? The only troubling thing here could be the \Bigg brackets #hint
    You can look up the rest on the internet or draw the symbols on kirelabs.

    People will also be much more likely to help you if you post your attempt which gives an error and the error itself.

     – Nepumuk Sep 30 '19 at 07:29
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    Perhaps to apply the advice of Descartes: " The second, to divide each of the difficulties that I would examine, into as many parcels as possible and that would be required to better solve them. " You can create intermediate variables and split your formula into simpler formulas. The expression will be easier to read. – gigiair Sep 30 '19 at 08:24
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    Please don't downvote below a score of -1, even if the question in its current form needs some improvement. A score of -1 is enough to show that the question needs work, anything below that is of no use. – BambOo Sep 30 '19 at 14:35
  • \begin{eqnarray} D_{ik}(t,\delta,C) = \sum_{c=0}^{\left[ \frac{\delta}{\tau}\right]}\Bigg(\displaystyle \prod_{r=1}^{e} \bar{q}{ic_n}^N(t.r) \sum{j=1}^N \sum_{m=1}^{N} \bar{q}^{m-1}{ic_j}(t,e)P{ic_j}^{\tau_{ic_j}^m}(t,e)\\nonumber \big(\frac{L} {\bar{\psi}^{\tau^{m}{ic_j}}{i{c_j}}(t)}+D_{cjk}(y,\delta)\big)+\sum_{e=1}^{\left[\frac{\delta}{\tau}\right]}\Big(\displaystyle\prod_{r=i}^{e} \bar{q}^{N}{ic_n}(t.r)e T(1-\bar{q}^{N}{icn}(t,e)\Big)\Bigg) \end{eqnarray} – Vaman Kulkarni Jun 16 '20 at 14:36

1 Answers1

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Here is a start. As explained in the above comments, what you want seems fairly easy to obtain, but I am too lazy to retype the whole thing :-)

\documentclass[12pt]{report}
\usepackage{mathtools}
\begin{document}
\begin{equation*}
\begin{aligned}
\mathcal{D}_{ik}(t) = 
&\sum_{j=1}^{\lfloor \frac{c}{d} \rfloor} \Bigg( \prod_{i=1}^{n} \Big( \text{some stuff} \Big) \Bigg)\\
& + {} \text{some other stuff}
\end{aligned}
\end{equation*}
\end{document}

enter image description here

Denis
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    Thanks, brother Denis for your time and effort....I will try to complete the other parts...thanks again. – Qusay Sep 30 '19 at 08:38
  • I'd prefer \lfloor c/d\rfloor. – egreg Sep 30 '19 at 10:17
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    @egreg Right. I was just trying to reproduce (part of) the example in which it seems that a \frac is used. – Denis Sep 30 '19 at 10:49
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    @Denis I liked how you give a starting point for the OP to have something to follow than doing all the work for them. – M. Al Jumaily Sep 30 '19 at 14:17
  • @M.AlJumaily Thanks for your comment. Giving a rough starting point is sometimes useful and does not prevent the OP from learning how to it, I hope. – Denis Oct 01 '19 at 13:36