I'm trying to draw a sine function going out from a particular point. When I use {sin(x r)} it gives kinked lines. When I use this code I get a lot of errors that say "Package pgf Error No shape named (0 is known. Package TikZ Error Giving up on this path. Did you forget a semicolon?.
Here is my code:
\foreach \x in {0, ..., 16}
\draw ((0.05+\x), (3.1+{sin(((pi*\x)/4) r)})) to [out=90*\x, in=(90*(1+\x))] ((0.5+(\x+1)*.25), ({sin((pi*(\x+1)/4) r)}+3.1));
Any advice is greatly appreciated.
*and braces where appropriate. Try\documentclass[tikz,border=3mm]{standalone} \begin{document} \begin{tikzpicture} \foreach \x in {0,...,16} {\draw ({0.05+\x},{3.1+sin(pi*\x/4 r)}) to [out=90*\x, in=90+90*\x] ({{0.5+0.25*(\x+1)}}, {sin(pi*(\x+1/4) r)+3.1});} \end{tikzpicture} \end{document}. There is no error but the output suggests you may have had something different in mind. – Dec 31 '19 at 18:37