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happy new year i want your help i would like to show which one below with a new line or one below each other but i can't find how to do it the code is here

$$\bm{X}=[ \bm{x}^{(1)} , \bm{x}^{(2)} ,\ldots ,\bm{x}^{(m)} ] \in \mathbb{R}^{(n,m} \bm{B}=[ \bm{b}^{(1)} , \bm{b}^{(2)}, \ldots , \bm{b}^{(m)}]  \in\mathbb{R}^{(n.m)} $$

enter image description here

David Carlisle
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constantinos georgiou
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    Regarding your use of $$ you might want to have a look at https://tex.stackexchange.com/q/40492/134144 – leandriis Jan 01 '20 at 15:38
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    Apart from that, please make your code compilable (See minimal working example (MWE)). – leandriis Jan 01 '20 at 15:40
  • Does `\documentclass{article} \usepackage{bm} \usepackage{amssymb} \usepackage{amsmath}

    \begin{document}

    \begin{align} \bm{X}&=[ \bm{x}^{(1)} , \bm{x}^{(2)} ,\ldots ,\bm{x}^{(m)} ] \in \mathbb{R}^{(n,m}\ \bm{B}&=[ \bm{b}^{(1)} , \bm{b}^{(2)}, \ldots , \bm{b}^{(m)}] \in\mathbb{R}^{(n.m)} \end{align}

    \end{document}` give you the desired result?

     – leandriis Jan 01 '20 at 15:42
  • @leandriis, till to now i didn't observe your comment :-(. Sorry! If you will convert it to an answer, I will delete mine. – Zarko Jan 01 '20 at 16:11
  • @Zarko: No problem: Let's keep your answer. – leandriis Jan 01 '20 at 16:32
  • @leandriis, thank you very much! Happy New Year! – Zarko Jan 01 '20 at 17:20

1 Answers1

4

I suspect that you looking for something like this:

\documentclass{article}
\usepackage{amsmath, amssymb}
\usepackage{bm}

    \begin{document}
\begin{align*}
\bm{X} & =[ \bm{x}^{(1)}, \bm{x}^{(2)}, \ldots, \bm{x}^{(m)}] \in \mathbb{R}^{(n.m)} \\
\bm{B} & =[ \bm{b}^{(1)}, \bm{b}^{(2)}, \ldots, \bm{b}^{(m)}] \in\mathbb{R}^{(n.m)}
\end{align*}
\end{document}

enter image description here

Note: you will make New Year Happy to us if you will in future questions always provide MWE (Minimal Working Example: a small complete document, which reproduce your problem) and with it help us to help you!

Zarko
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