Binomial tree in tikz

Question

I would love to have a nice tikz-version of this Word drawing of a tree from an exercise in game theory.

So far I've made the following:

\begin{tikzpicture}[level distance=1.5cm,
    level 1/.style={sibling distance=3cm},
    level 2/.style={sibling distance=1.5cm}]
   \node {$1$}
     child {node {$2$}
      child {node {$(4,1)$}}
      child {node {$(2,1)$}}
    }
     child {node {$2$}
      child {node {$(1,0)$}}
      child {node {$(0,4)$}}
    };
\end{tikzpicture}

But how do add the last details? Thanks.

https://tex.stackexchange.com/search?q=Binary+tree+tikz – Scott H. Jan 03 '20 at 14:57 — Scott H., Jan 03 '20 at 14:57

score 3 · Accepted Answer · edited Jan 03 '20 at 11:20

Off-topic for the tag: Using istgame package with a best alignment for the last trees:

\documentclass[a4paper,12pt]{article}
\usepackage{istgame}
\usepackage{amsmath}


\begin{document}
\begin{istgame}[scale=1,font=\footnotesize]
\setistDecisionNodeStyle{4pt}
\xtdistance{15mm}{30mm}
\istroot[0](0)[initial node]
<0>{}
\istb{R}[a]{\begin{matrix} 3 & \\ 1 \end{matrix}}[r] 
\endist
\xtdistance
{15mm}{2.5cm}
\istroot(0){$1$}
\istb{L}[al]
\istb{M}[ar]
\endist
\xtdistance{15mm}
{1cm}
\istroot(1)(0-1)<100>{$2$}
\istb{l}[l]{\begin{matrix} \phantom{44}4 & \\ \phantom{44}1 \end{matrix}}
\istb{r}[r]{\begin{matrix} \phantom{44}2 & \\ \phantom{44}1  \end{matrix}}
\endist
\istroot(2)(0-2)<45>
{$2$}
\istb{l}[l]{\begin{matrix} \phantom{44}1 & \\ \phantom{44}0 \end{matrix}}
\istb{r}[r]{\begin{matrix} 
\phantom{44}0 & \\ \phantom{44}4  \end{matrix}}
\endist
\end{istgame}
\end{document}

Another try of using istgame package, but without \phantom things:

\documentclass{article}    
\usepackage{amsmath}
\usepackage{istgame}   
\NewDocumentCommand\vpay{mm}
{\begin{matrix}#1\\#2\end{matrix}}

\begin{document}

\begin{istgame}
\setistDecisionNodeStyle{4pt}
\xtdistance{20mm}{15mm}
\istroot[east](0)
  \istb{R}[a]{\vpay31}[r]
  \endist
\xtdistance{15mm}{30mm}
\istroot(0){1}
  \istb{L}[al]
  \istb{M}[ar]
  \endist
\xtdistance{15mm}{15mm}
\istroot(1)(0-1)<135>{2}
  \istb{\ell}[l]{\vpay41}
  \istb{r}[r]{\vpay21}
  \endist
\istroot(2)(0-2)<45>{2}
  \istb{\ell}[l]{\vpay10}
  \istb{r}[r]{\vpay04}
  \endist
\end{istgame}

\end{document}

Nice solution (+1)! One day I will try to learn this package :-) — Zarko, Jan 03 '20 at 01:32

score 2 · Answer 2 · edited Jun 10 '20 at 12:32

With use of the forest package:

\documentclass[border=3mm]{standalone}
\usepackage{forest}
\begin{document}
\tikzset{ELS/.style={% Edge Label Style
      font=\footnotesize, inner sep=2pt,
      anchor=south #1, % label position: "ELS=west" or "ELS=east"
      pos=0.6},
      every label/.style = {font=\small\linespread{0.84}\selectfont,align=center,inner sep=2pt},
        }
%---------------------------------------------------------------%
    \begin{forest}
for tree={
  l sep=13 mm,
  s sep= 7 mm,
    where level=2{inner sep=0pt}{circle, fill, outer sep=0pt}
        },
   EL/.style = {% shortenes for edge label, defined as style
   before typesetting nodes={% edge labels positioning
    where n=1{%
      edge label/.wrap value={node[ELS=east]{#1}}% above left
    }{%
      edge label/.wrap value={node[ELS=west]{#1}}% above right
    }
                            }
                }
[,label=1, name=n1
    [,label=above left:2, EL=L
        [, label=below:4\ 1,EL=l]
        [, label=below:2\ 1,EL=r]
    ]
    [,label=above right:2, EL=M
        [, label=below:1\ 0,EL=l]
        [, label=below:0\ 4,EL=r]
    ]
]
    \draw (n1) -- node[font=\small\sffamily, above] {R} ++ (1.4,0) node[label=east:3\4] {};
    \end{forest}
\end{document}

Edit: Increased are distance between nodes:

Peraphs with istgame package could be more fast to create the tree. — Sebastiano, Jan 02 '20 at 16:54
@Sebastiano, very likely, however, I'm not familiar with this package ;-(. Please provide a solution using it! — Zarko, Jan 02 '20 at 16:57
Thank you. In the use of forest, how do I add more spacing between the end nodes? — mas2, Jan 03 '20 at 09:09

score 1 · Answer 3 · answered Jan 02 '20 at 22:54

Another forest option but without adding too much stuff by hand. It is just one tree, and the edge label is placed on the basis of the actual slope of the edge.

\documentclass[border=3mm]{standalone}
\usepackage[edges]{forest}
\tikzset{lbl/.style={circle,fill,inner sep=1.5pt,label=above:#1},
/forest/el/.style={edge label={
let \p1=($(.child anchor)-(!u.parent anchor)$),\n1={atan2(\y1,\x1)},
\n2={ifthenelse(cos(\n1)<0,\n1+90,\n1-90)} in
node[pos=1/2,anchor=\n2,font=\sffamily]{#1}}}}

\begin{document}

\begin{forest}
for tree={grow=south,
    l sep+=2em,
    s sep+=1em,
    edge+={thick},
    font=\sffamily
  }
[,label=above:3,label=below:1,grow'=west
 [,lbl=1,el=R
  [,lbl=2,el=L
   [4,label=below:1,el=l]
   [2,label=below:0,el=r]
  ]
  [,lbl=2,el=M
   [1,label=below:0,el=l]
   [0,label=below:4,el=r]
  ]
 ]
]
\end{forest}
\end{document}

Binomial tree in tikz

3 Answers3

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