Tikz foreach path between nodes starts at wrong position

Question

This picture

has been generated by following code. In red circles the edges start/end not on the correct side of the node.

\documentclass[tikz]{standalone}
% ==================================================
% GENREAL OBLIQUE CRYSTALLOGRAPHIC COORDINATE SYSTEM
% ==================================================
\makeatletter 
\tikzdeclarecoordinatesystem{general}
{%
  {%
    \pgf@xa=0pt% point
    \pgf@ya=0pt%
    \pgf@xb=0pt% sum
    \tikz@bary@dolist#1,=,%
    \pgfmathparse{1}%
    % modified from copy
    % /usr/local/texlive/2018/texmf-dist/tex/generic/pgf/frontendlayer/tikz/tikz.code.tex
    \global\pgf@x=\pgfmathresult\pgf@xa%
    \global\pgf@y=\pgfmathresult\pgf@ya%
  }%
}%
\makeatother
\begin{document}
\begin{tikzpicture}
\coordinate (A) at (0,-2);
\coordinate (B) at (3,0);

\path foreach \na in {0,...,2} { foreach \nb in {0,...,2} {
% Wyckoff letter 'a'
  (general cs:A=\na,B=\nb)
    node (a\na\nb) {2}
    % node     {a}
    node[yshift=0.5cm] {a\na\nb}
% Wyckoff letter 'b'
  \ifnum \nb&lt;2
   (general cs:A=\na,B=\nb+0.5)
   node (b\na\nb) {2}
    % node {b}
    node[yshift=0.5cm] {b\na\nb}
  \fi
}
};

% PROBLEM
\foreach \nb [evaluate=\nb as \nbnext using \nb+1] in {0,...,2} {
  \ifnum \nb&lt;2
    \draw (a0\nb) -- (b0\nb) -- (a0\nbnext);
  \fi
};

% NO PROBLEM:
% \draw (a00) -- (b00) -- (a01);
% \draw (a01) -- (b01) -- (a02);


\end{tikzpicture}
\end{document}

There is no problem when I use the commented code

\draw (a00) -- (b00) -- (a01);
\draw (a01) -- (b01) -- (a02);

I think my foreach loop produces the exact same code as I would write manually and I am completely suprised that tikz struggles here.

Update due to answer by Schrödinger's cat:

As pointed out simple integer arithmetic still results in a fixed point width number, e.g. 1+1=2.0. For instance, this is implicitly shown in section 95.3.1 Basic artihmetic functions of the pgf/tikz documentation of v3.1.5b:

81.0 \pgfmathparse{add(75,6)} \pgfmathresult

It can be verified by printing a0\nbext as the content of a node.

In this cirumstance this has the consequence that .0 is interpreted as anchor specification. The pgf/tikz documentation (Section 17.2.1 Syntax of the Node Command) already says that periods should not occur in node names:

Assigns a name to the node for later reference. Since this is a “high-level” name (drivers never know of it), you can use spaces, number, letters, or whatever you like when naming a node. Thus, you can name a node just 1 or perhaps start of chart or even y_1. Your node name should not contain any punctuation like a dot, a comma, or a colon since these are used to detect what kind of coordinate you mean when you reference a node.

Related questions:

score 3 · Accepted Answer · answered Jun 13 '20 at 19:38

It is the usual problem that, if you do not explicitly say you want integers, TikZ adds .0, which gets interpreted as an anchor, the east anchor in this case. All I did was to replace

[evaluate=\nb as \nbnext using \nb+1]

by

[evaluate=\nb as \nbnext using {int(\nb+1)}]

to obtain

\documentclass[tikz]{standalone}
% ==================================================
% GENREAL OBLIQUE CRYSTALLOGRAPHIC COORDINATE SYSTEM
% ==================================================
\makeatletter 
\tikzdeclarecoordinatesystem{general}
{%
  {%
    \pgf@xa=0pt% point
    \pgf@ya=0pt%
    \pgf@xb=0pt% sum
    \tikz@bary@dolist#1,=,%
    \pgfmathparse{1}%
    % modified from copy
    % /usr/local/texlive/2018/texmf-dist/tex/generic/pgf/frontendlayer/tikz/tikz.code.tex
    \global\pgf@x=\pgfmathresult\pgf@xa%
    \global\pgf@y=\pgfmathresult\pgf@ya%
  }%
}%
\makeatother
\begin{document}
\begin{tikzpicture}
\coordinate (A) at (0,-2);
\coordinate (B) at (3,0);

\path foreach \na in {0,...,2} { foreach \nb in {0,...,2} {
% Wyckoff letter 'a'
  (general cs:A=\na,B=\nb)
    node (a\na\nb) {2}
    % node     {a}
    node[yshift=0.5cm] {a\na\nb}
% Wyckoff letter 'b'
  \ifnum \nb&lt;2
   (general cs:A=\na,B=\nb+0.5)
   node (b\na\nb) {2}
    % node {b}
    node[yshift=0.5cm] {b\na\nb}
  \fi
}
};

% PROBLEM
\foreach \nb [evaluate=\nb as \nbnext using {int(\nb+1)}] in {0,...,2} {
  \ifnum \nb&lt;2
    \draw (a0\nb) -- (b0\nb) -- (a0\nbnext);
  \fi
};

% NO PROBLEM:
% \draw (a00) -- (b00) -- (a01);
% \draw (a01) -- (b01) -- (a02);


\end{tikzpicture}
\end{document}

Thank you for your help. I could verify the addition of .0 by printing a node with the content {a0\nbnext}. Do you happen to know where this is documented in the pgf/tikz documentation? The int() function is listed in subsection 95.3.2 Rounding functions of pgf/tikz 3.1.5b. — Hotschke, Jun 14 '20 at 09:10
@Hotschke The .0 is implicitly documented in all the functions you can look up except for those dealing with integers. What is relevant here is the addition, see the example \pgfmathparse{add(75,6)} \pgfmathresult on p. 1031. See also the statement "The result stored in the macro \pgfmathresult is a decimal without units. This is true regardless of whether the ⟨expression⟩ contains any unit specification." on p. 1026. Note also that you can use \the\numexpr\nb+1 instead of \nbnext (but you need to be a bit careful with the delimiters of this one). — , Jun 14 '20 at 09:19

Tikz foreach path between nodes starts at wrong position

1 Answers1