I have this working example:
\documentclass[letterpaper,12pt]{article}
\usepackage{hyperref}
\usepackage{amsmath}
\begin{document}
\begin{align}
\frac{d}{dx}&(\sin^{-1} x)=\frac{1}{\sqrt{1-x^2}} & \frac{d}{dx}&(\cos^{-1} x)=-\frac{1}{\sqrt{1-x^2}} \
\frac{d}{dx}&(\tan^{-1} x)=\frac{1}{1-x^2} & \frac{d}{dx}&(\cot^{-1} x)=-\frac{1}{1-x^2} \
\frac{d}{dx}&(\sec^{-1} x)=\frac{1}{ x \sqrt{x^2-1} & \frac{d}{dx}(\csc^{-1} x)=-\frac{1}{x \sqrt{x^2-1}}
\end{align}
\end{document}
Compiling gives this error
Runaway argument?
\frac {d}{dx}&(\sin ^{-1} x)=\frac {1}{\sqrt {1-x^2}} & \frac {d}{dx\ETC.
! Paragraph ended before \align* was complete.
<to be read again>
\par
l.13
I can't spot any errors with the align.
}in the third line of the equation. Use\frac{d}{dx}&(\sec^{-1} x)=\frac{1}{ x \sqrt{x^2-1}} & \frac{d}{dx}(\csc^{-1} x)=-\frac{1}{x \sqrt{x^2-1}}. – Nov 03 '20 at 07:55ds are also not entirely correct. Use\newcommand{\diff}{\mathop{}\!\mathrm{d}} \begin{align*} \frac{\diff}{\diff x}(\sin^{-1} x)&=\frac{1}{\sqrt{1-x^2}} & \frac{\diff}{\diff x}(\cos^{-1} x)&=-\frac{1}{\sqrt{1-x^2}} \\ \frac{\diff}{\diff x}(\tan^{-1} x)&=\frac{1}{1-x^2} & \frac{\diff}{\diff x}(\cot^{-1} x)&=-\frac{1}{1-x^2} \\ \frac{\diff}{\diff x}(\sec^{-1} x)&=\frac{1}{ x \sqrt{x^2-1}} & \frac{\diff}{\diff x}(\csc^{-1} x)&=-\frac{1}{x \sqrt{x^2-1}} \end{align*}– Nov 03 '20 at 07:58}. As for the alignment points, it is a common practice to align at the equality signs. As for the differential, this is an operator and is usually typeset in the same font as other operators, namely upright. (Already Gauss and Euler used the same fonts for functions likesinand the differentiald, but rumors say that they were not using LaTeX for some reason. ;-) – Nov 03 '20 at 08:11\sin^{-1}is wrong according to ISO regulations? – egreg Nov 03 '20 at 09:24