A rectangular shaped carpet with the grass

Question

I have a rectangular shaped carpet. Is it possible to create a specific code to simulate a grass carpet, like in a golf field?

\documentclass[tikz,border=5]{standalone}
\usepackage[prefix=]{xcolor-material}
\begin{document}
\begin{tikzpicture}[x=(330:1cm),y=(30:1cm),z=(90:1cm)]
\fill [LightGreen] (-1,-1,0) -- (-.5,1,0) -- (11,2,0) -- (11,-2,0) -- cycle;
\end{tikzpicture}
\end{document} 

Related question: Projectile motion: change an old code and make it more beautiful

Answer 1

I'm not sure whether there might be more elegant ways to do this, but here is my try. I might improve it in the next days if I can manage the grass to look more convincing, but LaTeX does not like too many computations and if you try to force too many "sprouts", it will stop compiling with a memory size error.

Warning: Compiling might take a little while.

Update #1: Changed the looks and color of grass for better effect.

Update #2: Changed a few parameters and how the coordinates are calculated, also using only brighter green color to make the grass more visible.

Output

Code

\documentclass[tikz,margin=10pt]{standalone}
\usepackage[prefix=]{xcolor-material}
\usetikzlibrary{calc}
\tikzset{
    grass/.style={thin, LightGreen!#1}
}
\newcommand\myangle{5}
\begin{document}
\begin{tikzpicture}[x=(330:1cm),y=(30:1cm),z=(90:1cm)]
\fill[LightGreen] (-1,-1,0) coordinate (c1) -- (-.5,1,0) coordinate (c2) -- (11,2,0) coordinate (c3) -- (11,-2,0) coordinate (c4) -- cycle ;
\foreach \x [count=\n] in {0,.005,...,1}{%
    \foreach \multiplier in {1,...,12}{%
        \pgfmathsetmacro\grad{random(80,90)}
        \pgfmathsetmacro\varA{random(1,100)}
        \pgfmathsetmacro\varB{random(1,100)}
        \pgfmathsetmacro\varC{random(1,100)}
        \pgfmathsetmacro\varD{random(1,100)}
        \pgfmathsetmacro\ciuf{rand/10}
    \coordinate (a\n) at ($(c1)!\x!(c4)$);
    \coordinate (b\n) at ($(c2)!\x!(c3)$);

    \path ($(a\n)!\varA/100!(b\n)$) 
        edge[grass=\grad, bend right=\myangle]++  (0,\ciuf pt,.1pt);

    \path ($(a\n)!\varB/100!(b\n)$) 
        edge[grass=\grad, bend right=\myangle]++  (0,\ciuf pt,.1pt);

    \path ($(a\n)!\varC/100!(b\n)$) 
        edge[grass=\grad, bend right=\myangle]++  (0,\ciuf pt,.1pt);

    \path ($(a\n)!\varD/100!(b\n)$) 
        edge[grass=\grad, bend right=\myangle]++  (0,\ciuf pt,.1pt);
}

}
\end{tikzpicture}
\end{document} 

Answer 2

The solution I propose is based on the idea of drawing grass blades through a decoration. Executing the code might take a while though; 60 seconds if next \j -\j=.02 in the \foreach loop.

grass decoration is introduced at the beginning. It uses multiple marks spaced apart by a given step, the argument of the decoration.

Then the grass is constructed along paths that follow the long side of the carpet (see the second figure where both steps are increased by a factor of 10 and the length of the blades by 2). In my opinion, in case this solution is considered, the main choices will turn around the colors needed to obtain the grass feeling.

The code:

\documentclass[border=1cm]{standalone}
\usepackage{tikz}
\usetikzlibrary{calc, math, decorations.markings}
\begin{document}
\xdefinecolor{GY}{RGB}{153, 235, 40}
\xdefinecolor{G}{RGB}{139, 214, 74}
\xdefinecolor{BG}{RGB}{58, 139, 33}
\tikzmath{%
  integer \N;
  real \step;
  \step=.01;
  \N = ceil(1/\step);
}
\tikzset{%
  grass/.style={%
    decorate,
    decoration={markings,
      mark=between positions 0 and 1 step{#1} with {%

        \pgfmathsetmacro{\tmp}{%
          \pgfkeysvalueof{/pgf/decoration/mark info/sequence number}}
        \pgfmathsetmacro{\tmpYG}{int(100-60sin((\tmp/\N+.25rand)90))}
        \pgfmathsetmacro{\tmpBG}{int(50-40sin((\tmp/\N+.5rand)90))}
        \pgfmathsetmacro{\r}{.1+(.3+.15rand)\tmp/\N}
        \pgfmathsetmacro{\a}{155+30rand}
        \pgfmathsetmacro{\dy}{rand4}
        \draw[G!\tmpYG!GY] (0, \dy pt) -- ++(\a: \r);
        \draw[BG!\tmpBG!G] (.3\dy pt, \dy pt) -- ++(\a+30\r: \r*.6);
      }
    }
  }
}
\begin{tikzpicture}[x=(330:1cm), y=(30:1cm), z=(90:1cm)]
  \path
  (-1, -1) coordinate (BW)
  (-.5, 1) coordinate (BE)
  (11, 2, 0) coordinate (FE)
  (11, -2, 0) coordinate (FW);
\clip (FW) -- ($(FE)+(0, .5pt)$) -- (BE) -- (BW) -- cycle;
  \fill[top color=BG!30!G, bottom color=G]
  (FW) -- (FE) -- (BE) -- (BW) -- cycle;
  \foreach \j in {0, .01, ..., 1}{%
    \path[postaction={grass={\step}}] ($(BE)!\j!(BW)$) -- ($(FE)!\j!(FW)$);
  }
\end{tikzpicture}
\end{document}