I am using amsmath package, and I would like to print $\dot{\overline{P}}^{A}$ such that the letter A was at the same height as in $\overline{P}^{A}$.
The order of upper symbols matters (\dot must be over \overline). Moving A inside \dot{} is also impossible since the dot moves horribly to the right. So how can the superscript be lowered down manually? Similar problem was asked here, however, the solution doesn't work for me.
Capture the height of \overline{P} via {\vphantom{\overline{P}}} and use that to add a superscript:
\documentclass{article}
\begin{document}
$\dot{\overline{P}}^A$
$\overline{P}^A$
$\dot{\overline{P}}{\vphantom{\overline{P}}}^A$
\end{document}
The above solution uses content from \vphantom and superscripts - specifically, {<vphantom>}^{<exp>}.
\vphantom then no need to measure, \dot{\overline{P}}\vphantom{\overline{P}}^A
– daleif
Jun 17 '21 at 05:20
\dot{\overline{P}}{}^{A}which is one of the answers that you link to. – David Carlisle Jun 16 '21 at 20:48{}hint in the code. Withamsmathincluded I got other results than presented in the answer, and this must have confused me. Silly, I know :( – Maverick Jun 16 '21 at 21:01