Here's a LuaLaTeX-based solution. The solution provides a Lua function called l2ell that does most of the actual work, along with two utility LaTeX macros, \lellOff and \lellOn, which deactivate and reactivate the l2ell function.
This approach will admittedly go astray on $\l$. However, as \l is a text-mode command (for the Polish "soft ell", to be specific), it shouldn't occur in math-y circumstances, right?

\documentclass{article}
\usepackage{luacode}
\begin{luacode}
function l2ell ( s )
s = s:gsub ( "^l(%A)" , "\\ell %1" )
s = s:gsub ( "(%A)l$" , "%1\\ell" )
s = s:gsub ( "(%A)l(%A)" , "%1\\ell %2" )
return s
end
\end{luacode}
% LaTeX macros to activate and deactivate the Lua function:
\newcommand\lellOn{\directlua{luatexbase.add_to_callback (
"process_input_buffer" , l2ell , "l2ell" )}}
\newcommand\lellOff{\directlua{luatexbase.remove_from_callback (
"process_input_buffer" , "l2ell" )}}
\AtBeginDocument{\lellOn} % activate the Lua function by default
\begin{document}
$\log l +\ln l= lb + l^2$, $l$, $ll$, $l + l$, $ l ^ l$
\lellOff % deactivate the Lua function
$\log l +\ln l= lb + l^2$, $l$, $ll$, $l + l$, $ l ^ l$
\end{document}
lbrepresents the multiplication oflandb, not the variablelb. For multi-letter mathematical symbols, one might use, for example,\mathrm{lb}. In this sense, your question might be considered ambiguous. – Steven B. Segletes Dec 02 '21 at 19:352/ Thanks!
– user182849 Dec 04 '21 at 23:06