I’m trying to draw a structure like that in Latex and I’m having a hard time. I know how to draw nodes using \node and how to draw arcs using \draw but I can’t connect the two.
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3 Answers
In order to help you starting with TikZ, here's a quick solution that reproduce your hand drawn design. Feel free to adapt it.
In the future, please consider adding a minimal working example (MWE) that illustrates your problem, starting with \documentclass{...} and ending with \end{document}.
\documentclass[tikz,border=3.14mm]{standalone}
\usetikzlibrary{chains}
\begin{document}
\begin{tikzpicture}[
start chain=going base right,
node distance=2cm,
every on chain/.append style=
{draw = violet,
circle,
inner sep=0pt,
minimum size=1cm,
line width=1pt,
font=\sffamily},
myedge/.style={line width=1pt, violet}]
\foreach \i in {1,...,6}
\node[on chain] (\i) {\i};
\foreach \i in {1,...,5}
{
\pgfmathtruncatemacro{\j}{\i+1}
\draw[myedge] (\i) -- (\j);
}
\draw[myedge] (1) to [out=90, in=0] ++(-2,3)
(2) to [out=90, in=180] ++(2,3)
(3) to [out=90, in=90, looseness=1.5] (4)
(5) to [out=90, in=180] ++(2,3);
\end{tikzpicture}
\end{document}
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Thank you so much. I'm new to latex and I didn't even know how to properly phrase my problem but that's exactly the structure I want. Thank you. – user267662 Apr 03 '22 at 16:11
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Where you find definition for
start chain = going base right? I made some experiments with it but so far didn't find and diference tostart chain = going right– Zarko Apr 03 '22 at 17:14 -
I found it a while ago in an example here on TeX-SX for a chain of
rectangle splitnodes with vertical split. This allowed nodes to be chained on the first split cell instead of the centers. Here it's useless. Try adding\node[on chain, text width=1cm] {NOW YOU KNOW};right after your chain of nodes and you'll see. – SebGlav Apr 03 '22 at 17:36 -
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1@SebGlav, thank you very much. Unfortunately this option is not documented in documentation ... – Zarko Apr 03 '22 at 18:22
A wee bit variation of nice @SebGlaw answer:
\documentclass[border=3.141592]{standalone}
\usepackage{tikz}
\usetikzlibrary{chains,
positioning}
\begin{document}
\begin{tikzpicture}[
node distance = 2cm, on grid,
start chain = going right, %
vertex/.style = {circle, draw = blue, thick,
minimum size=1em,
font=\sffamily,
on chain, join = by arr},
arr/.style = {draw=blue, semithick},
] ]
\foreach \i in {1,...,6}
\node[vertex] (\i) {\i};
\draw[arr] (1) edge [out=90, in=0] ++(-2,3)
(2) edge [out=90, in=180] ++( 2,3)
(3) edge [out=90, in=90,
min distance=15mm] (4)
(5) edge [out=90, in=180] ++(2,3);
\end{tikzpicture}
\end{document}
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Here is the way a beginner might approach this:
First, place the nodes at your desired coordinates using the \node command. Then use \draw to connect nodes as you wish. The to[out= , in=] describes the angle out and the angle in to get curved lines. Finally, ++(x,y) describes relative coordinates (right x, up y) from the node.
\documentclass{article}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}[every node/.style={circle, draw=blue, thick, inner sep=5pt}]
\node at (2,0)(A1){1};
\node at (4,0)(A2){2};
\node at (6,0)(A3){3};
\node at (8,0)(A4){4};
\node at (10,0)(A5){5};
\node at (12,0)(A6){6};
\draw[thick, blue] (A1)--(A2)--(A3)--(A4)--(A5)--(A6)
(A3) to[out=90, in=90] (A4)
(A1) to[out=90, in=0] ++(-1,2)
(A2) to[out=90, in=180] ++(1,2)
(A5) to[out=90, in=180] ++(1,2);
\end{tikzpicture}
\end{document}
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nodepackage you're talking about? The output you provided is very straightforward in TikZ. What did you try yet? – SebGlav Apr 03 '22 at 14:33