1

expected output but equation number should be auto

I want to get a single equation number for this multiple equation with \label I need for cross referencing. Also, I need a tall curly brace prior to the equation number.

Mico
  • 506,678

4 Answers4

2

mathtools has rcases

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\documentclass{article}

\usepackage{mathtools}

\begin{document}

\begin{equation} \label{eq:abc} \begin{rcases} \begin{alignedat}{3} \log L&=0 && \implies &u_1&=x\ \log L&=0 && \implies &u_2&=y \end{alignedat} \end{rcases} \end{equation} See \eqref{eq:abc} \end{document}

David Carlisle
  • 757,742
2

You can use alignedat, but you can exploit that the two equations have the same structure and the same width.

\documentclass{article}
\usepackage{amsmath}

\begin{document}

\begin{equation} \left. \begin{alignedat}{3} \frac{\partial}{\partial\mu_1}\log L &= 0 &\enspace\Rightarrow &\enspace& \hat{\mu}_1&=\bar{x}_1 \ \frac{\partial}{\partial\mu_2}\log L &= 0 &\enspace\Rightarrow &\enspace& \hat{\mu}_2&=\bar{x}_2 \end{alignedat} \right} \end{equation}

\begin{equation} \left. \begin{gathered} \frac{\partial}{\partial\mu_1}\log L = 0 ;\Rightarrow; \hat{\mu}_1=\bar{x}_1 \ \frac{\partial}{\partial\mu_2}\log L = 0 ;\Rightarrow; \hat{\mu}_2=\bar{x}_2 \end{gathered} \right} \end{equation}

\end{document}

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egreg
  • 1,121,712
1

Here's a solution that encases an array environment in a \left. ... \right\} construct.

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\documentclass{article} % or some other suitable document class

\usepackage{array} % for '\newcolumntype' macro \newcolumntype{C}{>{{}}c<{{}}} % for mathbin and mathrel objects \newcolumntype{L}{>{\displaystyle}l} \newcolumntype{R}{>{\displaystyle}r} \usepackage{booktabs} % for '\addlinespace' macro

\setlength\textwidth{4in} % just for this example \counterwithin{equation}{section} \begin{document} \setcounter{section}{16} % just for this example \setcounter{equation}{44}

\begin{equation} \label{eq:hello} \setlength\arraycolsep{0pt} % default value: 5pt \left. \begin{array}{ RCL @{\quad} c @{\quad} RCL } \frac{\partial}{\partial\mu_1} \log L &=& 0 &\Rightarrow& \hat{\mu}_1 &=& \bar{x}_1 \ \addlinespace \frac{\partial}{\partial\mu_2} \log L &=& 0 &\Rightarrow& \hat{\mu}_2 &=& \bar{x}_2 \end{array} \right} \end{equation} A cross-reference to equation (\ref{eq:hello}). \end{document}

Mico
  • 506,678
1

Another solution, with the drcases environment, to ensure \displaystye inside rcases, and the diffcoeff package, which eases typesetting partial derivatives (and also ordinary derivatives):

    \documentclass{article} % or some other suitable document class
\usepackage{mathtools}
\usepackage{diffcoeff}

\begin{document}

\begin{equation}\label{eqn}
\begin{drcases}
\diffp*{\log L}{\mu_1} = 0 \implies &amp; \widehat{\mu}_1 = \bar{x}_1 \\[1ex]
\diffp*{\log L}{\mu_2} = 0 \implies &amp; \widehat{\mu}_2 = \bar{x}_1
\end{drcases}
\end{equation}

\end{document} 

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Bernard
  • 271,350