I'd like to have the usual symbol for the infimal convolution. I've tried \stackrel{+}{\vee}, but it scales down the plus, which I don't want. I also tried \atop, but the symbol gets really big and ugly. I'd like something more like \pm... But unfortunately I'm having a hard time finding its code.
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Claudia
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Infimal convolution symbols across the Internet vary, so this one is taken from Wikipedia:

\documentclass{article}
\usepackage{amsmath,amssymb}% http://ctan.org/pkg/{amsmath,amssymb}
\DeclareMathOperator{\iconv}{\mathbin{\star_{\text{inf}}}}%
\begin{document}
\[ (f\iconv g)(x) = \inf\{f(x-y)+g(y)\,\vert\,y\in\mathbb{R}^n\} \]
\end{document}
Here's another one taken from this source:

\documentclass{article}
\usepackage{amsmath,amssymb}% http://ctan.org/pkg/{amsmath,amssymb}
\usepackage{graphicx}% http://ctan.org/pkg/graphicx
\DeclareMathOperator{\iconv}{%
\mathbin{\ooalign{\raisebox{-.5ex}{$\vee$}\cr\hidewidth\raisebox{.5ex}{\scalebox{.7}{+}}\hidewidth}}}%
\begin{document}
\[ (f\iconv g)(x) = \inf\{f(x-y)+g(y)\,\vert\,y\in\mathbb{R}^n\} \]
\end{document}
Or, create it yourself (from the above, and therefore does not require graphicx):

\documentclass{article}
\usepackage{amsmath,amssymb}% http://ctan.org/pkg/{amsmath,amssymb}
\DeclareMathOperator{\iconv}{%
\mathbin{\ooalign{\raisebox{-.5ex}{$\triangledown$}\cr\hidewidth\rule[.3ex]{.4pt}{1ex}\hidewidth}}}%
\begin{document}
\[ (f\iconv g)(x) = \inf\{f(x-y)+g(y)\,\vert\,y\in\mathbb{R}^n\} \]
\end{document}
If you're going to use these symbols in super-/subscripts, then more works needs to be done. The use of \ooalign for symbol construction is discussed in \subseteq + \circ as a single symbol (“open subset”).
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Thanks. The symbol I was looking for is a plus sign over a vee. But you gave me an idea: maybe I should use
\mathbininstead of\mathrel, which I am using now... – Claudia Sep 01 '12 at 20:36
\star? – Hendrik Vogt Sep 01 '12 at 20:11\newcommand\plusvee{\mathrel{\ooalign{\lower.5ex \hbox{$\scriptstyle\vee\mkern.5mu$}\cr\hidewidth\raise.450ex \hbox{$\scriptstyle+$}\cr}}}– Claudia Sep 01 '12 at 20:31