2

enter image description here

The current formula I have is:

\begin{displaymath}
1 = \frac{1}{\cfrac{2}{1-\cfrac{1}{3}}}
\end{displaymath}

How should I proceed further?

Zarko
  • 296,517

2 Answers2

7

Se if the following is what you after:

\documentclass{article}
\usepackage{amsmath}

\begin{document} [ 1 = \frac{\tfrac{1}{2}}{1-\cfrac{\tfrac{1}{3}}{1-\cfrac{\tfrac{1}{4}}{1-\cfrac{\tfrac{1}{5}}{1-\cfrac{\tfrac{1}{6}}{1-\tfrac{1}{7}}}}}} ] \end{document}

enter image description here

Zarko
  • 296,517
4

This seems quite similar to the picture.

\documentclass{article}
\usepackage{amsmath,array}

\begin{document}

[ \setlength{\arraycolsep}{1pt} \renewcommand{-}{{}-{}}% local redefinition, harmless 1=; \begin{array}[t]{*{10}{c}} \multicolumn{3}{c}{\dfrac{\kern1pt 1 \kern1pt}{2\mathstrut}} \ \cline{1-3} 1 & - & 1 \ \cline{3-3}\noalign{\kern1pt} && 3 \ \cline{3-5} && 1 & - & 1 \ \cline{5-5}\noalign{\kern1pt} &&&& 4 \ \cline{5-7} &&&& 1 & - & 1 \ \cline{7-7}\noalign{\kern1pt} &&&&&& 5 \ \cline{7-9} &&&&&& 1 & - & 1 \ \cline{9-9}\noalign{\kern1pt} &&&&&&&& 6 \[-2ex] &&&&&&&&& \ddots \end{array} ]

\end{document}

enter image description here

egreg
  • 1,121,712