How to get (print) the number of elements in the row with the largest number of elements in the array?

Question

For example, in the following MWE, there're 12 elements in the first line of the array while the second line of the array has 10 elements, so I'd like a command that can automatically printed the number of elements in the row with the largest number of elements in the array: 12.

MWE:

\documentclass[tikz]{standalone}
\ExplSyntaxOn
\seq_new:N \l_node_row_seq  
\seq_new:N \l_node_tmp_seq 
\cs_set:Npn \timelist #1 {
  \seq_set_split:Nnn \l_node_row_seq {;} {#1}
  \int_step_inline:nn{\seq_count:N \l_node_row_seq}
  {
    \seq_if_exist:cF {l_node_row_##1_seq}
    {
      \seq_new:c {l_node_row_##1_seq}
    }
    \exp_args:Ncx\seq_set_from_clist:Nn {l_node_row_##1_seq} {\seq_item:Nn \l_node_row_seq{##1}}
  }
}
\cs_set:Npn \PrintTime [#1][#2] {
  \tl_if_empty:nTF { #1 }
  {
    \tl_if_empty:nTF { #2 }
    {
      \seq_use:Nn \l_node_row_seq {,}
    }
    {
      \int_step_inline:nn{\seq_count:N \l_node_row_seq}
      {
        \seq_put_right:Nn \l_node_tmp_seq {\seq_item:cn {l_node_row_##1_seq}{#2}}
      }
      \seq_use:Nn \l_node_tmp_seq {,}
    }
  }
  {
    \tl_if_empty:nTF {#2}
    {
      \seq_use:cn {l_node_row_#1_seq}{,}
    }
    {
      \seq_item:cn {l_node_row_#1_seq}{#2}
    }
  }
}
\ExplSyntaxOff
\usetikzlibrary{calc}
\begin{document}
\timelist{
3,.,1,4,1,5,9,2,6,5,3,5;
2,.,7,1,8,2,8,1,8,2}
\tikz
{
\foreach \x in {1,2,...,12}
    {
      \node[xshift=.5\x in] at (-\x,1) {\texttt{\PrintTime[1][\x]}};
      \node[xshift=.5\x in] at (-\x,0) {\texttt{\PrintTime[2][\x]}};
    }
}
\end{document}

Now if there's a command, for example, the name of the command is count, then if I input

\count{
3,.,1,4,1,5,9,2,6,5,3,5;
2,.,7,1,8,2,8,1,8,2
}

Then it will print 12 automatically. How can I realize it?