8

How can I get matrices that are side by side? Currently I have the following:

\[
\begin{pmatrix}[ccc|c]
1&2&0&0\\
-1&1&2&0\\
1&0&1&5\\
0&-2&1&4
\end{pmatrix}
\]
\[
\begin{pmatrix}[ccc|c]
1&2&0&0\\
0&3&2&0\\
0&-2&1&5\\
0&-2&1&4
\end{pmatrix}
\]

What I want is the matrices to go across the paper with row equivalence signs on them (I am showing a reduced echelon form matrix)

David Carlisle
  • 757,742

4 Answers4

11

Don't use two separate environments for displyed math. As Mico has suggested in his answer, it's better to use array environments.

In the following example I defined two environments, one for the matrices and another one for the elementary row operations; I also defined two commands for two of the row operations. Using an alignat environment you can align the matrices and their operations:

\documentclass{article}
\usepackage{amsmath}
\usepackage{array}

\newenvironment{redmatrix}
  {\left(\array{@{}rrr|c@{}}}
  {\endarray\right)}
\newenvironment{ropmatrix}
  {\array{@{}c@{}}}
  {\endarray}
\newcommand\opone[2]{\xrightarrow{(#1)\times r_#2}}
\newcommand\optwo[3]{\xrightarrow{r_#1{}+{} #2r_#3}}

\begin{document}
\begin{alignat*}{5}
&
\begin{redmatrix}
1&2&0&0\\
-1&1&2&0\\
1&0&1&5\\
0&-2&1&4
\end{redmatrix}
&
\begin{ropmatrix}
\optwo{1}{}{2}
\end{ropmatrix}
&
\begin{redmatrix}
1&2&0&0\\
0&3&2&0\\
0&-2&1&5\\
0&-2&1&4
\end{redmatrix}
&
\begin{ropmatrix}
\opone{1/3}{2}
\end{ropmatrix}
&
\begin{redmatrix}
1&2&0&0\\
0&1&2/3&0\\
0&-2&1&5\\
0&-2&1&4
\end{redmatrix}\\
&&
\begin{ropmatrix}
\optwo{3}{2}{2}\\
\optwo{4}{2}{2}\\
\end{ropmatrix}
&
\begin{redmatrix}
1&2&0&0\\
0&1&2/3&0\\
0&0&7/3&5\\
0&0&7/3&4
\end{redmatrix}
&
\begin{ropmatrix}
\opone{3/7}{3}
\end{ropmatrix}
&
\begin{redmatrix}
1&2&0&0\\
0&1&2/3&0\\
0&0&1&15/7\\
0&0&7/3&4
\end{redmatrix}
\end{alignat*}

\end{document}

enter image description here

Mico
  • 506,678
Gonzalo Medina
  • 505,128
5

Are you looking for \sim ("row equivalence sign")? (Also: *matrix doesn't take an optional parameter.)

Code

\documentclass{article}
\begin{document}
\[
\left(\begin{array}{@{}ccc|c@{}}
     1 &  2 & 0 & 0 \\
    -1 &  1 & 2 & 0 \\
     1 &  0 & 1 & 5 \\
     0 & -2 & 1 & 4
\end{array}\right)
\sim
\left(\begin{array}{@{}ccc|c@{}}
    1 &  2 & 0 & 0 \\
    0 &  3 & 2 & 0 \\
    0 & -2 & 1 & 5 \\
    0 & -2 & 1 & 4
\end{array}\right)
\]
\end{document}

Output

enter image description here

Improvement

If you use those matrices more than once you can define a new environment that does this for you:

\documentclass{article}
\newenvironment{rowequmat}[1]{\left(\array{@{}#1@{}}}{\endarray\right)}
\begin{document}
\[
\begin{rowequmat}{ccc|c}
     1 &  2 & 0 & 0 \\
    -1 &  1 & 2 & 0 \\
     1 &  0 & 1 & 5 \\
     0 & -2 & 1 & 4
\end{rowequmat}
\sim
\begin{rowequmat}{ccc|c}
    1 &  2 & 0 & 0 \\
    0 &  3 & 2 & 0 \\
    0 & -2 & 1 & 5 \\
    0 & -2 & 1 & 4
\end{rowequmat}
\]
\end{document}
Qrrbrbirlbel
  • 119,821
4

I suggest you use array instead of pmatrix environments, as arrays give you more flexibility with regard to the positioning of the elements of a column, and also let you insert vertical bars. Separately, don't specify two separate display math environments, but only one. Here's an MWE:

\documentclass{article}
\usepackage{array}
\begin{document}
\[
\left(\begin{array}{@{}rrr|c@{}}
1&2&0&0\\
-1&1&2&0\\
1&0&1&5\\
0&-2&1&4
\end{array}\right)
\quad
\left(\begin{array}{@{}rrr|c@{}}
1&2&0&0\\
0&3&2&0\\
0&-2&1&5\\
0&-2&1&4
\end{array}\right)
\]
\end{document}

enter image description here

Mico
  • 506,678
-2
\documentclass{article}
\usepackage{array}
\begin{document}

 \[
\left(\begin{array}{cccccc}1&-2&0&2&0&1\\0&0&1&5&0&-3\\0&0&0&0&1&6\\0&0&0&0&0&0\end{array}\right|\left.\begin{array}{c}1\\-1\\1\\0\end{array}\right) 
\]

\end{document}
Stefan Kottwitz
  • 231,401
Eva
  • 1
  • Thanks for your participation, Eva, but the code you provided (without any sort of explanation) does not produce the output desired by the person who asked the question. – Clément Feb 13 '16 at 04:10