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I would like to find some directories via

find /path/to/a/dir -type d  -links 2

and then for each pathname found by find, assumed to be stored in variable pathname, I would like to 

stow -d "$(dirname "$pathname")" -t /home/t/bin "$(basename "$pathname")"

How can I combine the above with find -exec, something similar to:

find /path/to/a/dir -type d  -links 2 -exec stow -d "$(dirname \{\})" -t /home/t/bin "$(basename \{\})" \;

I think it doesn't work because the shell performs the command substitutions before running find, and no pathname is found yet to replace \{\} in the command substitutions.

Thanks.

Tim
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1 Answers1

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You wrap it in a sh -c command

find /path/to/dir -type d -links 2 -exec sh -c 'stow -d "$(dirname "$1")" -t /home/t/bin "$(basename "$1")"' sh {} \;
  • Thanks. Why do you use sh instead of bash here? – Tim Dec 02 '18 at 14:14
  • sh is guaranteed to exist on any Unix system. On linux, /bin/sh is either a symlink to /bin/bash itself (eg. rhel, centos) or to something smaller and faster (/bin/dash on ubuntu and debian). –  Dec 02 '18 at 14:28