How do I pass a quote that has a space at the end as an argument in bash?

Asked Apr 01 '21 at 11:28

Active Apr 01 '21 at 11:28

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Say I have a shell script at ~/script.sh:

TEST="$1 $2"
echo $TEST

And I run it with bash ~/script.sh "he " "he",

The output of the command will be he he, but I expected it to be he he because the first argument, which is quote, has a space as the last character of the quote.

asked Apr 01 '21 at 11:28

Setoshi Nekomoto

2

Does this answer your question? Why does my shell script choke on whitespace or other special characters? In short: echo "$TEST". – Kamil Maciorowski Apr 01 '21 at 11:30
Even better with printf '%s\n' "$TEST" as echo may modify the contents of the string under some circumstances (like interpreting \n as "newline"). – Kusalananda Apr 01 '21 at 11:52

How do I pass a quote that has a space at the end as an argument in bash?

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