ok so im trying to read the output of a command

Question

echo -en "date: "
read sdate
mdate="date -d '${sdate} 00:00:00' +%s "
udate(){ 
$mdate 
}
udate

output

root@Xanarchy:/cnc# bash date
date: 01-01-2000
date: extra operand ‘+%s’
Try 'date --help' for more information.

What you're doing there falls squarely in "How can we run a command stored in a variable?". Here, you'd be best off just spelling the command out in the function instead of using a variable. But you're not reading the output of the command there, at all. You'd need output=$(date ...) or so for that. — ilkkachu, Nov 24 '21 at 18:16
Please [edit] your post and i) ask a question; ii) explain what you are trying to do and how it fails and iii) give a descriptive title: remember that the title is all people see when looking at the home page, so if you don't explain what the question is in the title, people will ignore it. — terdon, Nov 24 '21 at 18:17
Does this answer your question? How can we run a command stored in a variable? — Greenonline, Nov 25 '21 at 04:06

score 0 · Answer 1 · answered Nov 24 '21 at 21:08

0

echo -en "date: "
read sdate
mdate=(date -d "${sdate} 00:00:00" +%s)
udate(){
"${mdate[@]}"
}
udate

Using a string makes this unnecessarily complicated. Using an array is much simpler.

01-01-2000 is illegal input for date. You need 2000-01-01.

answered Nov 24 '21 at 21:08

Hauke Laging

1 Answers1