which command returning undocumented things

Question

I am trying to locate which conda executable I am using. For this, I want to use which command. As per man pages, it should return the path of the executable. Instead it returns some bash function

(base) ➜  ~ which conda
conda () {
    \local cmd="${1-__missing__}"
    case "$cmd" in
        (activate | deactivate) __conda_activate "$@" ;;
        (install | update | upgrade | remove | uninstall) __conda_exe "$@" || \return
            __conda_reactivate ;;
        (*) __conda_exe "$@" ;;
    esac
}

If I try to see the location of __conda_exe, again I get another function:

__conda_exe () {
    (
        __add_sys_prefix_to_path
        "$CONDA_EXE" $_CE_M $_CE_CONDA "$@"
    )
}

where is the conda function I am using?

You've tagged your question bash - are you actually using zsh however? — steeldriver, Jul 01 '22 at 08:08
If using zsh try typing which -p conda to see the path instead of the script. Starting version 4.4, conda uses a wrapper shell function to capture commands and pass it to the executable. If you want to know the version, you should use conda --version — Michael Harvey, Jul 01 '22 at 11:52
In zsh type __conda_exe (same as whence -v, while which is whence -c, c for csh as which is initially a csh script for csh users) will tell you where the function definition was read from. — Stéphane Chazelas, Jul 02 '22 at 08:47

score 1 · Answer 1 · answered Jul 02 '22 at 13:55

1

Since you’re using zsh, I would recommend using the following:

whence -aSv conda

This will show you all the possible ways in which conda can be resolved.

answered Jul 02 '22 at 13:55

Marlon Richert

3,869

which command returning undocumented things

1 Answers1