Draw two planes of Cartesian equation: y=3-x and z=2+x with Plot3D

Question

I have two Cartesian equation of plans: y=3-x and z=2+x. I want to draw both planes with Plot3D but I don't know what I have to put in the fonction.

This link could be useful: http://www.math.uconn.edu/~hurley/math220/Mathematica_docs/Planes.pdf — mattiav27, Oct 22 '16 at 09:36
I rather wish it could be marked a duplicate of both...The first is almost general enough, but the later question seems a closer duplicate, especially by virtue of its answers. — Michael E2, Oct 22 '16 at 15:21

score 1 · Answer 1 · edited Apr 13 '17 at 12:56

1

Plot3D plots $f(x,y)$ as a function of $(x,y)$. The second plane, $z=2+x$ can be plotted with

Plot3D[2 + x, {x, -10, 10}, {y, -10, 10}]

The first plane, $f(x,y)=x+y-3\equiv 0$, so it won't work. But ContourPlot3D works for any plane $ax+by+cz+d=0$:

ContourPlot3D[{y == 3 - x, z == 2 + x}, {x, -10, 10}, {y, -10, 10}, {z, -5, 5}]

Draw two planes of Cartesian equation: y=3-x and z=2+x with Plot3D

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