Computing the Lyuponov exponent for the Duffing system

Question

Does anyone know (simple) Mathematica code for computing the Lyuponov exponent for the Duffing system?

x''[t] + 0.15 x'[t] - x[t] + x[t]^3== 7*Cos[t]
{x[0] == 0, x'[0] == 0}

The system is in chaotic state but I got negative values for Lyapunov Exponents by using the suggested methods I am not sure what is wrong — Kaleed Ad, Nov 05 '18 at 17:48
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score 5 · Accepted Answer · answered Nov 06 '18 at 18:41

5

My previous code for LyapunovExponents from this answer did not handle non-autonomous systems like this properly. Thanks for pointing that out! I've updated it to fix this mistake and it seems to work now.

Putting your system in first-order form:

eqns = {x'[t] == y[t], y'[t] == -0.15 y[t] + x[t] - x[t]^3 + 7 Cos[t]};

Then calculating Lyapunov exponents:

LyapunovExponents[eqns, {x -> 0, y -> 0}, ShowPlot -> True]

Mathematica graphics

(* {0.10542, -0.25542} *)

answered Nov 06 '18 at 18:41

Chris K

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I used your code after your modification and I was able to get very close results for this work https://arxiv.org/pdf/physics/0303077.pdf for this eq: eqns = {x'[t] == y[t], y'[t] == 2.5*Sin[t] - 0.1 y[t] - Sin[x[t]]}; This is what I got {0.160632, -0.260632} And this what they got {0.160 , −0.262} That is very good By the way, should I always use the initial conditions for LyapunovExponents[eqns, {x -> 0, y -> 0}, ShowPlot -> True]
or the value for x and y at any time is fine? Thanks you
– Kaleed Ad Nov 06 '18 at 19:27
Great, thanks for the link. You can use whatever initial conditions (t=0) you want. – Chris K Nov 06 '18 at 20:22

Computing the Lyuponov exponent for the Duffing system

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