Remove mesh triangles in contour plot

Question

How do I get rid of the mesh in this contour plot?

 ContourPlot[x^2 + y^2, {x, -10, 10}, {y, -10, 10}, 
    Contours -> {1.0, 4.0, 10.5}, ContourStyle -> None, 
    ContourShading -> {RGBColor[1, .2, 0, .1], RGBColor[1, .2, 0, .3], 
    RGBColor[1, .2, 0, .5], RGBColor[1, .2, 0, .7]}]

enter image description here

Setting the option Mesh->None doesn't help. I'm using Mathematica 12.1.1

That's odd I don't see this in 12.1.1 Windows 10. Try adding MeshStyle -> None or BaseStyle->{EdgeForm[None]} and see if that makes a difference. — flinty, Aug 02 '20 at 01:24
Still problematic with those options set. I'm on MacOS 10.13.6 — QuantumDot, Aug 02 '20 at 01:40

score 7 · Accepted Answer · answered Aug 02 '20 at 02:00

From Removing unwanted appearance of underlying mesh, which is a duplicate:

ContourPlot[x^2 + y^2, {x, -10, 10}, {y, -10, 10}, 
 Contours -> {1.0, 4.0, 10.5}, ContourStyle -> None, 
 ContourShading -> {RGBColor[1, .2, 0, .1], RGBColor[1, .2, 0, .3], 
   RGBColor[1, .2, 0, .5], RGBColor[1, .2, 0, .7]}, 
 Method -> {"TransparentPolygonMesh" -> True}]

score 2 · Answer 2 · answered Aug 02 '20 at 01:46

The mesh comes from reducing the opacity. To avoid the mesh, use fully opaque colors.

$Version
(* "12.1.1 for Mac OS X x86 (64-bit) (June 19, 2020)" *)
Clear["Global`*"]
ContourPlot[x^2 + y^2, {x, -10, 10}, {y, -10, 10},
 Contours -> {1.0, 4.0, 10.5},
 ContourStyle -> None,
 ContourShading ->
  {LightRed, Pink, Red, Darker[Red]}]

Remove mesh triangles in contour plot

2 Answers2