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Basically, I'm trying to "rotate" a plot clockwise so that the former x-axis is pointing down, and the former y-axis is pointing to the right. From reading some answers on here, I gathered that I can get axes in the right general orientations using ParametricPlot:

ParametricPlot[{Sin[7 x] - 1,x}, {x, 0, 1}, 
  PlotRange -> {{-3, 0}, {0, 1}}, 
  Frame -> True, 
  AspectRatio -> 5/8, 
  FrameLabel -> {"Label 1", "Label 2"}]

plot

But the problem is that the vertical axis still points up, and I need it to be going the other direction: I need it to be 0 at the top and 1 at the bottom.

Does anyone have any solution to this? ScalingFunctions would have worked beautifully from what I've been reading, but this seems to have been "fixed" years ago without a similar functionality put in to replace it.

Any help is appreciated!

m_goldberg
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Steve
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  • If I understand correctly, try ParametricPlot[{Sin[7x]-1, -x}, {x,0,1}] i.e. flip the new "y" by adding a minus sign. – Bill Feb 16 '15 at 04:51
  • That does seem to work, but the frame labels are now wrong, as in the labels are negative. Is there a way to fix that? – Steve Feb 16 '15 at 04:57
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    does Rotate[plot,-Pi/2] work? – Basheer Algohi Feb 16 '15 at 05:05
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  • @Algohi. Your approach has an issue -- it also rotates the frame labels and the tick labels, which I think is not wanted. – m_goldberg Feb 16 '15 at 05:20
  • Yup, I want the frame labels and tick labels to have proper orientations. Oh, and thanks for fixing the code block, m_goldberg. – Steve Feb 16 '15 at 05:22
  • Related: (6204898), (7191), (7859), (13253), (18655) – Mr.Wizard Feb 16 '15 at 13:45
  • I have marked this as a duplicate. I believe what you want is accomplished through FrameTicks. Does this not give the correct output?: ParametricPlot[{Sin[7 x] - 1, -x}, {x, 0, 1}, Frame -> True, FrameTicks -> {Automatic, {-#, #} & /@ Range[0, 1, 0.2]}] – Mr.Wizard Feb 16 '15 at 13:51
  • In Mathematica 10 ScalingFunctions does work too: ParametricPlot[{Sin[7 x] - 1, x}, {x, 0, 1}, Frame -> True, ScalingFunctions -> {Identity, "Reverse"}] – Mr.Wizard Feb 16 '15 at 13:54
  • @Mr.Wizard. To get what the OP wants, you have to invert the aspect ratio and swap the frame labels as in my answer. – m_goldberg Feb 16 '15 at 14:27
  • @m_goldberg Sorry, I should have left those out entirely; such parameters were immaterial to the underlying method. – Mr.Wizard Feb 16 '15 at 14:31

2 Answers2

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Perhaps this is what you are looking for.

ParametricPlot[{t, - (Sin[7 t] - 1)}, {t, 0, 1}, 
  PlotRange -> {{0, 1}, {0, 3}},
  AspectRatio -> 8/5,
  FrameTicks -> {{Table[{i, -i}, {i, 0., 3., .5}], None}, {Automatic, None}},
  Frame -> True,
  FrameLabel -> {"Label 2", "Label 1"}]

plot

m_goldberg
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1

Just for fun (but somewhat ridiculous to me):

With[{r = RotationMatrix[-Pi/2]}, 
 ParametricPlot[r.{Sin[7 x] - 1, x}, {x, 0, 1}, 
  PlotRange -> (r.{{-3, 0}, {0, 1}}), Frame -> True, 
  AspectRatio -> 5/8, FrameLabel -> {"Label 1", "Label 2"}]]

enter image description here

ubpdqn
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