Displaying table with equations

Question

How can I display this table with an equation? I tried many times but i can't find any solution to display the table

    \documentclass{article}
    \usepackage[margin=25mm]{geometry}
    \usepackage{mathtools}
\usepackage[table]{xcolor}
\usepackage{booktabs, collcell, makecell, tabularx, threeparttable, multirow}
    \newcommand{\tclr}[1]{\textcolor{blue!70!black}{#1}}
    \newcolumntype{L}{&gt;{\collectcell\tclr\raggedright}X&lt;{\endcollectcell}}
   %{\textwidth}{@{} &gt;{\raggedright\arraybackslash}X &gt;{$\displaystyle}l&lt;{$} @{}}

\usepackage{xparse}
\NewExpandableDocumentCommand\mcc{O{1}m}
    {\multicolumn{#1}{c}{#2}}

\DeclarePairedDelimiter{\abs}{\mid}{\mid}

\begin{document}


\begin{table}
\centering
\begin{tabularx}{\textwidth}{@{}
                            L l
                       *{3}{&gt;{$\displaystyle}l&lt;{$}S}
                            @{}}
\toprule
MOP &amp; Definition &amp; Constraints\\
\midrule
\multirow{3}{*}{Schaffer Problem}
&amp; $F=(f_1(x),f_2(x))$ &amp; $-10^5\leq x\leq 10^5$ \\
&amp; $f_1(x)=x^2,$       &amp; \\
&amp; $f_2(x)=(x-2)^2$    &amp; \\
\midrule
\multirow{4}{*}{Viennet (3)}
&amp; $ F=(f_1(x,y),f_2(x,y),f_3(x,y))$                          &amp; $-4\leq x,y\leq4 $ \\
&amp; $ f_1(x,y)=0.5(x^2+y^2)+sin(x^2+y^2),$                     &amp; \\
&amp; $ f_2(x,y)=\frac{(3x-2y+4)^2}{8}+\frac{(x-y+1)^2}{27}+15,$ &amp; \\
&amp; $ f_3(x,y)=\frac{1}{x^2+y^2+1}-1.1 e^{-x^2-y^2}$           &amp; \\
\midrule
\multirow{3}{*}{Kursawe problem}
&amp; $ F=(f_1(\mathbf{x}),f_2(\mathbf{x}))$                                                           &amp; $-5\leq x_i\leq5$ \\
&amp; $ f_1(\mathbf{x})=\sum_{i=1}^{n-1}\left(-10 \exp\left(-0.2\sqrt{x_i^2+y_{i+1}^2}\right)\right),$ &amp; $i=1,2,3$ \\
&amp; $ f_2(\mathbf{x})=\sum_{i=1}^n\left(\abs{x_i}^{0.8}+5 sin(x_i^3)\right)$                         &amp; \\
\midrule
\multirow{4}{*}{Dep problem}
&amp; $ F=(f_1(x,y),f_2(x,y))$                                   &amp; $0\leq x,y\leq1$ \\
&amp; $ f_1(x,y)=x$,                                             &amp; \\
&amp; $ f_2(x,y)=(1+10y)\Bigl(1-\Bigl(\frac{x}{1+10y}\Bigr)^2- $ &amp; \\
&amp; $ \qquad \qquad \frac{x}{1+10y}sin(2p\pi x)\Bigr)$         &amp; \\
\bottomrule
\end{tabularx}
\caption{Unconstrained Functions}
\label{unconstrained}
\end{table}


\end{document}

Zarko · Answer 1 · 2022-04-28T15:33:59.637

With tabularray with columns in display math and in-line math mode the table code is simple:

\documentclass{article}
\usepackage[margin=25mm]{geometry}
\usepackage{tabularray}
\UseTblrLibrary{amsmath, booktabs}
\begin{document}
    \begin{table}
\begin{tblr}{colspec ={@{} l X[l, mode=dmath] Q[c,mode=math] @{}},
             row{1} = {mode=text},
             rowsep = 3pt
             }
    \toprule
MOP & Definition
        & Constraints                   \
    \midrule
\SetCell[r=3]{l}   Schaffer Problem
    &   F=(f_1(x),f_2(x)) 
        &   -10^5\leq x\leq 10^5        \
    &   f_1(x)=x^2
        &                               \
    & f_2(x)=(x-2)^2
        &                               \
    \midrule
\SetCell[r=4]{l}   Viennet (3)
    & F=(f_1(x,y),f_2(x,y),f_3(x,y))

        & -4\leq x,y\leq4               \
    & f_1(x,y)=0.5(x^2+y^2)+\sin(x^2+y^2)

        &                               \
    & f_2(x,y)=\frac{(3x-2y+4)^2}{8}+\frac{(x-y+1)^2}{27}+15

        &                               \
    &   f_3(x,y)=\frac{1}{x^2+y^2+1}-1.1 e^{-x^2-y^2}

        &                               \
    \midrule
\SetCell[r=3]{l}   Kursawe problem
    &   F=(f_1(\mathbf{x}),f_2(\mathbf{x}))
        & -5\leq x_i\leq5               \
    & f_1(\mathbf{x})=\sum_{i=1}^{n-1}\left(-10 \exp\left(-0.2\sqrt{x_i^2+y_{i+1}^2}\right)\right)
        & i=1,2,3                       \
    & f_2(\mathbf{x})=\sum_{i=1}^n\left(|{x_i}|^{0.8}+5 \sin(x_i^3)\right)
        &                               \
    \midrule
\SetCell[r=3]{c}   Dep problem
    &   F=(f_1(x,y),f_2(x,y))
        & 0\leq x,y\leq1                \
    & f_1(x,y)=x
        &                               \
    & f_2(x,y)=(1+10y)\Bigl(1-\Bigl(\frac{x}{1+10y}\Bigr)^2- \frac{x}{1+10y}\sin(2p\pi x)\Bigr)
        &                               \
    \bottomrule
\end{tblr}
    \end{table}
\end{document}

score 2 · Answer 2 · answered Apr 28 '22 at 21:10

You might use \multirow for this, but I prefer not to.

I solve the problem by stating the equations and the constraints in a single top aligned array; the rows are separated by \addlinespace to add some air (changing \arraystretch would not work as well).

\documentclass{article}
\usepackage[margin=25mm]{geometry}
\usepackage{mathtools}
\usepackage[table]{xcolor}
\usepackage{booktabs,array}
\DeclarePairedDelimiter{\abs}{\lvert}{\rvert}
\ExplSyntaxOn
\NewDocumentCommand{\addvertspaces}{m}
 {
  \seq_set_split:Nnn \l_tmpa_seq { \ } { #1 }
  \seq_use:Nn \l_tmpa_seq { \ \addlinespace }
 }
\ExplSyntaxOff
\begin{document}
\begin{table}[htp]
\centering
% a local command to ease input
\newcommand{\prob}[1]{$\begin{array}[t]{@{}>{\displaystyle}l@{}}\addvertspaces{#1}\end{array}$}
\newcommand{\constr}[1]{$\begin{array}[t]{@{}c@{}}\addvertspaces{#1}\end{array}$}
\begin{tabular}{\textwidth}{
  @{}
  >{\color{blue!70!black}}l
  @{\extracolsep{\fill}}
  l
  c
  @{}
}
\toprule
MOP & Definition & Constraints\
\midrule
Schaffer Problem & 
\prob{
  F=(f_1(x),f_2(x)) \
  f_1(x)=x^2, \
  f_2(x)=(x-2)^2
} &
\constr{-10^5\leq x\leq 10^5} \
\midrule
Viennet (3) &
\prob{
  F=(f_1(x,y),f_2(x,y),f_3(x,y)) \
  f_1(x,y)=0.5(x^2+y^2)+\sin(x^2+y^2), \
  f_2(x,y)=\frac{(3x-2y+4)^2}{8}+\frac{(x-y+1)^2}{27}+15, \
  f_3(x,y)=\frac{1}{x^2+y^2+1}-1.1 e^{-x^2-y^2}
} &
\constr{-4\leq x,y\leq4} \
\midrule
Kursawe problem &
\prob{
  F=(f_1(\mathbf{x}),f_2(\mathbf{x})) \
  f_1(\mathbf{x})=\sum_{i=1}^{n-1}\bigl(-10 \exp(-0.2\sqrt{\smash[b]{x_i^2+y_{i+1}^2}},)\bigr), \
  f_2(\mathbf{x})=\sum_{i=1}^n \bigl(\abs{x_i}^{0.8}+5 \sin(x_i^3)\bigr)
} &
\constr{i=1,2,3 \ -5\leq x_i\leq5} \
\midrule
Dep problem &
\prob{
  F=(f_1(x,y),f_2(x,y)) \
  f_1(x,y)=x, \
  f_2(x,y)=(1+10y)\Bigl(1-\Bigl(\frac{x}{1+10y}\Bigr)^2 
           -\frac{x}{1+10y}\sin(2p\pi x)\Bigr)
} &
\constr{0\leq x,y\leq1} \
\bottomrule
\end{tabular}
\caption{Unconstrained Functions}
\label{unconstrained}
\end{table}
\end{document}

Note that \mid is not a delimiter. Also the sine function should always be \sin. I used a trick in order to reduce the size of the square root.

score 1 · Accepted Answer · answered Apr 28 '22 at 07:32

Important things first. When dealing with new things, acquiring new skills, etc. keep things simple, do examples only with strictly necessary information. Everything else is a disturb and makes things susceptible to errors. This is the philosophy behind MWEs. You gonna read along the answer all methodology I used to find the issue, identify your objetive with this table and only then applying a solution.

That said, the first problem I found was: Package array Error: Illegal pream-token (S): 'c' used. \end{tabularx}. You used a column type named S which was not defined. You also defined (or let definitions someone else gave you) which were not used. Therefore, next step, change usage of S to anything basic, like l or c. Next, remove also non necessary packages and commands.

At this point we have the first working table with: \begin{tabularx}{\textwidth}{@{} l l c @{}}. Now the rain's gone.

It became clear you use sin instead of \sin. Checked and corrected. You created a special \abs delimiter, as it could be prone to errors, I removed it and let |x_i| where it was being used. Reinsert it, if it is necessary on anything else.

Finally I understood your real intention with your \newcolumntype. You wanted a column with \displaystyle. Following this answer

Table of displayed formulae

I created: \newcolumntype{L}{>{$\displaystyle} l <{$}}. Applying L in the tabularx we got an error: Missing $ inserted. \end{tabularx}. Basically, we are using $ twice, so let's remove it (a job for: Search and Replace). I chose to create a new table in order to be clear and didactic.

I used at this second table \textrm{Definition} and \text{Constraints} because they are text, not math. you may choose between both command options. To finish, let's use \renewcommand{\arraystretch}{1.8} from:

How to set the space between rows in a table

to make the table a lit bit more readable.

The MWE follows:

\documentclass{article}
\usepackage[margin=25mm]{geometry}
\usepackage{mathtools}
\usepackage{booktabs, tabularx, multirow}
\newcolumntype{L}{>{$\displaystyle} l <{$}}
\begin{document}
\begin{table}
  \centering
  \begin{tabularx}{\textwidth}{@{} l l c @{}}
    \toprule
    MOP                               & Definition                                                                                     & Constraints            \
    \midrule
    \multirow{3}{}{Schaffer Problem} & $F=(f_1(x),f_2(x))$                                                                            & $-10^5\leq x\leq 10^5$ \
                                      & $f_1(x)=x^2$                                                                                   &                        \
                                      & $f_2(x)=(x-2)^2$                                                                               &                        \
    \midrule
    \multirow{4}{}{Viennet (3)}      & $F=(f_1(x,y),f_2(x,y),f_3(x,y))$                                                               & $-4\leq x,y\leq4 $     \
                                      & $f_1(x,y)=0.5(x^2+y^2)+\sin(x^2+y^2)$                                                          &                        \
                                      & $f_2(x,y)=\frac{(3x-2y+4)^2}{8}+\frac{(x-y+1)^2}{27}+15$                                       &                        \
                                      & $f_3(x,y)=\frac{1}{x^2+y^2+1}-1.1 e^{-x^2-y^2}$                                                &                        \
    \midrule
    \multirow{3}{}{Kursawe problem}  & $F=(f_1(\mathbf{x}),f_2(\mathbf{x}))$                                                          & $-5\leq x_i\leq5$      \
                                      & $f_1(\mathbf{x})=\sum_{i=1}^{n-1}\left(-10 \exp\left(-0.2\sqrt{x_i^2+y_{i+1}^2}\right)\right)$ & $i=1,2,3$              \
                                      & $f_2(\mathbf{x})=\sum_{i=1}^n\left(|{x_i}|^{0.8}+5 \sin(x_i^3)\right)$                         &                        \
    \midrule
    \multirow{3}{}{Dep problem}      & $F=(f_1(x,y),f_2(x,y))$                                                                        & $0\leq x,y\leq1$       \
                                      & $f_1(x,y)=x$                                                                                   &                        \
                                      & $f_2(x,y)=(1+10y)\Bigl(1-\Bigl(\frac{x}{1+10y}\Bigr)^2- \frac{x}{1+10y}\sin(2p\pi x)\Bigr)$    &                        \
    \bottomrule
  \end{tabularx}
\end{table}
\begin{table}
  \renewcommand{\arraystretch}{1.8}
  \centering
  \begin{tabularx}{\textwidth}{@{} l L L @{}}
    \toprule
    MOP                               & \textrm{Definition}                                                                          & \text{Constraints}   \
    \midrule
    \multirow{3}{}{Schaffer Problem} & F=(f_1(x),f_2(x))                                                                            & -10^5\leq x\leq 10^5 \
                                      & f_1(x)=x^2                                                                                   &                      \
                                      & f_2(x)=(x-2)^2                                                                               &                      \
    \midrule
    \multirow{4}{}{Viennet (3)}      & F=(f_1(x,y),f_2(x,y),f_3(x,y))                                                               & -4\leq x,y\leq4      \
                                      & f_1(x,y)=0.5(x^2+y^2)+\sin(x^2+y^2)                                                          &                      \
                                      & f_2(x,y)=\dfrac{(3x-2y+4)^2}{8}+\frac{(x-y+1)^2}{27}+15                                      &                      \
                                      & f_3(x,y)=\dfrac{1}{x^2+y^2+1}-1.1 e^{-x^2-y^2}                                               &                      \
    \midrule
    \multirow{3}{}{Kursawe problem}  & F=(f_1(\mathbf{x}),f_2(\mathbf{x}))                                                          & -5\leq x_i\leq5      \
                                      & f_1(\mathbf{x})=\sum_{i=1}^{n-1}\left(-10 \exp\left(-0.2\sqrt{x_i^2+y_{i+1}^2}\right)\right) & i=1,2,3              \
                                      & f_2(\mathbf{x})=\sum_{i=1}^n\left(|{x_i}|^{0.8}+5 \sin(x_i^3)\right)                         &                      \
    \midrule
    \multirow{3}{}{Dep problem}      & F=(f_1(x,y),f_2(x,y))                                                                        & 0\leq x,y\leq1       \
                                      & f_1(x,y)=x                                                                                   &                      \
                                      & f_2(x,y)=(1+10y)\Bigl(1-\Bigl(\frac{x}{1+10y}\Bigr)^2- \frac{x}{1+10y}\sin(2p\pi x)\Bigr)    &                      \
    \bottomrule
  \end{tabularx}
\end{table}
\end{document}

First table with $ and default \arraystretch.

Second table using \newcolumntype with displaystyle and \renewcommand{\arraystretch}{1.8}.

Displaying table with equations

3 Answers3