I'm trying to make two lines intersect using the (intersection cs: first line={}, second line={}) syntax. However, compilation of the following example doesn't do what I want:
%!TEX encoding = UTF-8 Unicode
%!TEX program = lualatex
\documentclass[11pt,a4paper,fleqn,pdftex]{report}
\usepackage[dvipsnames, table]{xcolor}
\usepackage[utf8]{luainputenc}
\usepackage[latin,english]{babel}
\usepackage{tikz}
\usetikzlibrary{patterns}
\usetikzlibrary{shapes.geometric}
\begin{document}
\begin{figure}[!h]
\centering
\begin{tikzpicture}
\coordinate (S) at (-5 ,0);
\coordinate (M'1) at (0,4.5);
\coordinate (M2) at (0,3);
\def\angleM{10}
\draw[color=Red, thick] (M'1) -- (intersection cs: first line={(M'1)--++(90 - \angleM:-8)}, second line={(-5,-5) -- (5,5)}) circle (2pt) -- (S); % (S) -> (M'1)
\draw[color=Red, thick] (M2) -- (intersection cs: first line={(M2) --++(90 - \angleM:-8)}, second line={(45:-4) -- (45:4)}) circle (2pt) -- (S); % (S) -> (M2)
\draw (S) node[ellipse, fill=white, minimum height=3cm,minimum width=2mm,draw]{$(S)$};
\begin{scope}[thick]
\draw[densely dashed] (M'1) ++(1,0) -- ++(-2,0) node[left]{$M'_1$};
\draw (M2) ++(1,0) -- ++(-2,0) node[left]{$M_2$};
\end{scope}
\fill[pattern=north east lines] (M'1) ++(1,0) rectangle ++(-2,0.2);
\fill[pattern=north east lines] (M2) ++(1,0) rectangle ++(-2,0.2);
\draw[very thick] (45:-2) -- (45:2);
\end{tikzpicture}
\end{figure}
\end{document}
This code yields this:

Whereas I want the red lines to intersect with the black line in the center. Is there something I'm doing wrong? The PGF/TikZ manual doesn't provide any example of the intersection syntax with relative paths.

topath, for example) you can leave spaces, but in this case, they are not allowed (I don't really know if this is a design choice, since they are allowed before, but not after the--). Another case in which this restriction applies is when using theanglepic in which you cannot use spaces, so you have to use {angle = A--B--C} and not{angle = A -- B -- C}. – Gonzalo Medina Feb 20 '15 at 20:16