new command for the dx of intergral.

Question

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What’s the proper way to typeset a differential operator?

\newcommand{d}[1]{\:\textrm{d}{#1}}

That is my new comamnd for writing the dx of an intergral. Just wanted to be able to type this in my code.

\d{x}  <<<where the x is the variable of integration>>>

What did I do wrong?

Related Question: Should I \mathrm the d in my integrals? – Peter Grill Nov 17 '12 at 07:56 — Peter Grill, Nov 17 '12 at 07:56

score 9 · Accepted Answer · 2012-11-17T08:00:16.923

9

\newcommand\d[1]{\:\textrm{d}#1} 
\renewcommand\d[1]{\:\textrm{d}#1} % if \d is already defined

only for a definition of an environment you use \newenvironment{env}. Another useful definition is:

\newcommand*\diff{\mathop{}\!\mathrm{d}}

in your definition you do not really need the argument and using \mathrm makes more sense, then it takes the d from the same math font and not from the text font

\documentclass{article}
\renewcommand\d[1]{\:\textrm{d}#1}
\newcommand*\diff{\mathop{}\!\mathrm{d}}
\begin{document}
$\d x \textrm{ or } \diff x  $
\end{document}

edited Nov 17 '12 at 08:00

answered Nov 17 '12 at 07:44

Ok. uh. so what do I type in the body? – MaoYiyi Nov 17 '12 at 07:49
\d{x} or \d x or \diff x – Nov 17 '12 at 07:52
2

@MaoYiyi: You should not use \d as that is already used elsewhere. – Peter Grill Nov 17 '12 at 07:53
@Herbert that didn't work. – MaoYiyi Nov 17 '12 at 07:57
1

@MaoYiyi: "that didn't work" is not a helpful message ... As Peter already mentioned, if the \d is already defined (for an accent), then use \renewcommand\d – Nov 17 '12 at 07:59
@herbert, Sorry that I couldn't say more, I wish I could explain the messages that winEdt gives for wrong code. I used. – MaoYiyi Nov 17 '12 at 08:02
@Herbert \newcommand\dx[1]{:\textrm{d}#1} and that worked. I am very happy for you helpping me. You are very smart. – MaoYiyi Nov 17 '12 at 08:02
@MaoYiyi: see my edited answer – Nov 17 '12 at 08:04
When I type I like to have the {} around stuff, personal taste. So I was wondering would \newcommand*\diff[1]{\mathop{}!\mathrm{d}#1} work propertly? – MaoYiyi Nov 17 '12 at 08:07
1

@MaoYiyi: sure makes no difference – Nov 17 '12 at 08:17
This \diff may cause a problem when being used with the tipa package, since the package redefined \!. A possible solution with amsmath is replacing \! in your definition by \negthinspace. – Ch'en Meng Sep 02 '16 at 02:48
or simply use \mkern-\thinmuskip – Sep 02 '16 at 06:49

new command for the dx of intergral.

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