I am using this from the function repository for which I need to convert one of my functions into a unique form. A simple example is like this:
Suppose I have,
H[px_, py_, x_, y_] := 1/2 (px^2 + py^2) + (x^2 + y^2) + 1/2 x^2 y^2
and I need to convert this into a pure function with a particular form:
H := Function[{S}, 1/2 (S[[2]]^2 + S[[4]]^2) + S[[1]]^2 + S[[3]]^2 + 1/2 S[[1]]^2 S[[3]]^2]
The simple way I do this is by using,
H[px, py, x, y] /. x -> S[[1]] /. px -> S[[2]] /. y -> S[[3]] /. py -> S[[4]]
But this approach gives me warning messages. Is there a more elegant way by which I can automate the entire process?

hPure = H[#[[2]], #[[4]], #[[1]], #[[3]]] &? – Domen Mar 04 '24 at 08:18hPure = H[px, py, x, y] /. {x -> S[[1]], px -> S[[2]], y -> S[[3]], py -> S[[4]]} // Quiet. It's not entirely clear what the actual final form should be. Which function from the WFR are you using? – Domen Mar 04 '24 at 08:27Hstands for hamiltonian. I am dealing with a system with magnetic field, so every time I change the value of the field, my hamiltonian changes, now if I wish to use the hamiltonian that I calculated to generate a Poincare section using this resource function, I have to alter it's form. It's a repetitive process so manually doing it every time is not so efficient, that's why I was searching for some automation. – codebpr Mar 04 '24 at 09:06hMagnetic[b_] := Function[{S}, 1/2 (S[[2]]^2 + S[[4]]^2 + S[[1]]^2 + S[[3]]^2) + 2*S[[1]]^2 S[[3]] + b S[[3]]], and then callResourceFunction["ClickPoincarePlot2D"][..., hMagnetic[0.1], ...]. Please provide more concrete example of what you are using, otherwise, it seems like an XY problem. – Domen Mar 04 '24 at 09:20"Part specification S[[1]] is longer than depth of object"which makes sense sinceSis undefined. – bmf Mar 04 '24 at 09:22